插入触发器后更新另一个表的列的mysql

Dea*_*edy 27 mysql triggers sql-update

我正在尝试编写一个触发器,我有以下表格:BookingRequest:

  +-----------+---------+------+-----+---------+----------------+
    | Field     | Type    | Null | Key | Default | Extra          |
    +-----------+---------+------+-----+---------+----------------+
    | idRequest | int(11) | NO   | PRI | NULL    | auto_increment |
    | roomClass | int(11) | NO   |     | NULL    |                |
    | inDate    | date    | NO   |     | NULL    |                |
    | outDate   | date    | NO   |     | NULL    |                |
    | numOfBeds | int(11) | NO   |     | NULL    |                |
    | status    | int(11) | NO   | MUL | NULL    |                |
    | idUser    | int(11) | NO   | MUL | NULL    |                |
    +-----------+---------+------+-----+---------+----------------+
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状态表:

+------------+--------------------------------------------------+------+-----+---------+-------+
| Field      | Type                                             | Null | Key | Default | Extra |
+------------+--------------------------------------------------+------+-----+---------+-------+
| idStatus   | int(11)                                          | NO   | PRI | NULL    |       |
| nameStatus | enum('underConsideration','approved','rejected') | YES  |     | NULL    |       |
+------------+--------------------------------------------------+------+-----+---------+-------+
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OccupiedRoom:

+--------------+---------+------+-----+---------+----------------+
| Field        | Type    | Null | Key | Default | Extra          |
+--------------+---------+------+-----+---------+----------------+
| idOccupation | int(11) | NO   | PRI | NULL    | auto_increment |
| idRoom       | int(11) | NO   |     | NULL    |                |
| idRequest    | int(11) | NO   |     | NULL    |                |
+--------------+---------+------+-----+---------+----------------+
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我需要一个触发器,如果​​具有相同ID的请求被插入OccupiedRoom表,将在BookingReques中将状态更改为1,所以我尝试了这样的事情

create trigger occupy_trig after insert on OccupiedRoom 
for each row
begin
  if BookingRequest.idRequest= NEW.idRequest
   then
       update BookingRequest
       set status = '1';
       where idRequest = NEW.idRequest;

    end if;
END;
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并且它不起作用,所以任何建议都会非常有用

use*_*035 30

试试这个:

DELIMITER $$
CREATE TRIGGER occupy_trig
AFTER INSERT ON `OccupiedRoom` FOR EACH ROW
begin
       DECLARE id_exists Boolean;
       -- Check BookingRequest table
       SELECT 1
       INTO @id_exists
       FROM BookingRequest
       WHERE BookingRequest.idRequest= NEW.idRequest;

       IF @id_exists = 1
       THEN
           UPDATE BookingRequest
           SET status = '1'
           WHERE idRequest = NEW.idRequest;
        END IF;
END;
$$
DELIMITER ;
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pet*_*erm 28

随着你的要求,你不需要BEGIN ENDIF不必要的SELECT在你的扳机.所以你可以简化它

CREATE TRIGGER occupy_trig AFTER INSERT ON occupiedroom 
FOR EACH ROW
  UPDATE BookingRequest
     SET status = 1
   WHERE idRequest = NEW.idRequest;
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  • @DeadKennedy为什么不把它作为公认的答案?它会帮助其他人看看这个答案. (2认同)