对不起这样的菜鸟问题.
我只是按照谷歌加登录的Step1到Step4. https://developers.google.com/+/web/signin/ 登录似乎成功,同时出现错误'未知RPC服务:widget-interactive-I0_1370237493291'.以下是Chrome上的控制台日志.
XHR finished loading: "https://plusone.google.com/_/scs/apps-static/_/js/k=oz.connect.en_US.B31L_d…sv=1/d=1/ed=1/am=GA/rs=AItRSTOhxGvE7YZFbwjOy6nLkxCnNjz3og/cb=gapi.loaded_1". signin:15
XHR finished loading: "https://plusone.google.com/_/scs/apps-static/_/js/k=oz.gapi.en.hgKKOofQjvI.…sv=1/d=1/ed=1/am=EQ/rs=AItRSTOeNwU4i5ApX9gPGjnZ0AzovKWmWw/cb=gapi.loaded_0". signin:15
Unknown RPC service: widget-interactive-I0_1370237493291 cb=gapi.loaded_0:71
signed in
Run Code Online (Sandbox Code Playgroud)
我认为错误是关于不完整的事情.我无法弄清楚错误是什么以及如何弄清楚.我错过了什么?
这是代码.起源是http://localhost:3000
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>Gplus</title>
</head>
<body>
<h1>Gplus</h1>
<span id="signinButton">
<span
class="g-signin"
data-callback="signinCallback"
data-clientid="362449793624.apps.googleusercontent.com"
data-cookiepolicy="single_host_origin"
data-requestvisibleactions="http://schemas.google.com/AddActivity"
data-scope="https://www.googleapis.com/auth/plus.login">
</span>
</span>
<script type="text/javascript">
function signinCallback(authResult) {
if (authResult['access_token']) {
// Successfully authorized
// Hide the sign-in button now that the user is authorized, for example:
document.getElementById('signinButton').setAttribute('style', 'display: none');
console.log('signed in');
} else if (authResult['error']) {
// There was an error.
// Possible error codes:
// "access_denied" - User denied access to your app
// "immediate_failed" - Could not automatically log in the user
// console.log('There was an error: ' + authResult['error']);
}
}
</script>
<!-- Place this asynchronous JavaScript just before your </body> tag -->
<script type="text/javascript">
(function() {
var po = document.createElement('script'); po.type = 'text/javascript'; po.async = true;
po.src = 'https://apis.google.com/js/client:plusone.js';
var s = document.getElementsByTagName('script')[0]; s.parentNode.insertBefore(po, s);
})();
</script>
</body>
</html>
Run Code Online (Sandbox Code Playgroud)
当我尝试该代码示例时,我遇到了同样的问题。当我试图弄清楚这个问题时,我发现了这篇文章:
https://groups.google.com/forum/?fromgroups#!topic/google-plus-developers/Ax3cMLhMR4Q
在 Google+ 开发者论坛中,这似乎表明这并不是真正的“错误”,而是某种警告。如果我发现更多信息,我会在这里发布更新。
希望这可以帮助。
| 归档时间: |
|
| 查看次数: |
1662 次 |
| 最近记录: |