use*_*123 7 c# sql-server datagridview
我正在使用此视频尝试填充a的结果DataGridView,并收到上述错误.下面的代码与此错误有关 - 我将值传递给存储过程,然后最终SELECT返回表中的值DataGridView.
        SqlConnection con = new SqlConnection();
        con.ConnectionString = "integrated security=SSPI;data source=SERV;" + "persist security info=False;initial catalog=DB";
        con.Open();
        SqlCommand select = new SqlCommand("SELECT * FROM Table");
        SqlCommand enter = new SqlCommand("sp_Proc", con);
        // Stored Procedure
        enter.CommandType = CommandType.StoredProcedure;
        enter.Parameters.Add(new SqlParameter("@vvalue", SqlDbType.VarChar)).Value = Convert.ToString(txt1.Text);
        enter.Parameters.Add(new SqlParameter("@dvalue", SqlDbType.Decimal)).Value = Convert.ToDecimal(txt2.Text);
        enter.ExecuteNonQuery();
        // DataGrid returns the SELECT
        SqlDataAdapter sadapt = new SqlDataAdapter(select);
        sadapt.SelectCommand = select;
        DataTable dtab = new DataTable();
        sadapt.Fill(dtab); // generates the error
        BindingSource b = new BindingSource();
        b.DataSource = dtab;
        dGrid.DataSource = b;
        sadapt.Update(dtab);
        con.Close();
Joh*_*Woo 14
你没有传递connection对象command.试试这个,
SqlCommand select = new SqlCommand("SELECT * FROM Table", con);
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