Python相当于C++中的短格式"if"

Question

可能重复:
Python三元运算符

有没有办法用Python编写这个C/C++代码？ a = (b == true ? "123" : "456" )

Answer 1

a = '123' if b else '456'

Answer 2

虽然a = 'foo' if True else 'bar'是更现代的方式来执行三元if语句(python 2.5+),但是你的版本的1对1等价物可能是:

a = (b == True and "123" or "456" )

...在python中应缩短为:

a = b is True and "123" or "456"

......或者如果你只想测试一般b值的真实性......

a = b and "123" or "456"

? : 可以从字面上换掉 and or

Answer 3

我神秘的版本......

a = ['123', '456'][b == True]