clojure(with-timeout ... macro)

Art*_*ldt 8 clojure

我正在寻找一个宏,如果表达式需要超过X秒才能完成异常.

Tim*_*ley 22

这个问题在这里有更好的答案: 执行超时功能

期货来救援!

user=> (let [f (future (reduce * (range 1 1001)))]
  (.get f 1 java.util.concurrent.TimeUnit/MILLISECONDS))
java.util.concurrent.TimeoutException (NO_SOURCE_FILE:0)
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并制作一个宏:

(defmacro time-limited [ms & body]
  `(let [f# (future ~@body)]
     (.get f# ~ms java.util.concurrent.TimeUnit/MILLISECONDS)))
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所以你可以这样做:

user=> (time-limited 1 (reduce * (range 1 1001)))
java.util.concurrent.TimeoutException (NO_SOURCE_FILE:0)
user=> (time-limited 1 (reduce * (range 1 101)))
93326215443944152681699238856266700490715968264381621468592963895217599993229915
608941463976156518286253697920827223758251185210916864000000000000000000000000
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  • 超时后,未来可能会继续存在.超时后使用`future-cancel`,如[此主题]中所述(http://stackoverflow.com/a/6697469/682672). (5认同)