从弹出窗口返回一个值

Question

我有像下面这样的弹出窗口类.

public class Popup extends PopupWindow {

Context context;
EditText et_bankname, et_banknumber;
String bank_name, account_number;

public Popup(Context ctx) {
    super(ctx);
    context = ctx;

    setContentView(LayoutInflater.from(context).inflate(R.layout.bank_details, null));
    setHeight(WindowManager.LayoutParams.WRAP_CONTENT);
    setWidth(WindowManager.LayoutParams.WRAP_CONTENT);
    View popupView = getContentView();
    setFocusable(true);
    Button btn_close = (Button) popupView.findViewById(R.id.popupClose);
    Button btn_submit = (Button) popupView.findViewById(R.id.popupSave);
    et_bankname = (EditText) popupView.findViewById(R.id.bank_name);
    et_banknumber = (EditText) popupView.findViewById(R.id.bankacc_no);
    btn_submit.setOnClickListener(new OnClickListener() {

        public void onClick(View v) {
            bank_name = et_bankname.getText().toString();
            account_number = et_banknumber.getText().toString();
            if (!bank_name.equals("") && !account_number.equals("")) {      
                Toast t1 = Toast.makeText(context,bank_name + " "+account_number , Toast.LENGTH_SHORT);
                t1.setGravity(Gravity.TOP, 0, 100);
                t1.show();                  
                dismiss();                              
            } else {
                Toast t1 = Toast.makeText(context,
                        "Please provide valid details", Toast.LENGTH_SHORT);
                t1.setGravity(Gravity.TOP, 0, 100);
                t1.show();
            }
        }
    });
}

public void show(View v) {
    showAtLocation(v, Gravity.CENTER, 0, 0);
}
}

我将在我的活动中访问此弹出窗口

Popup popup = new Popup(getBaseContext());
popup.show(arg1);

这非常有效.但我想知道这个弹出窗口何时被解雇.为此目的,我现在使用Thread如下概念.

if (isPopupShowing) {
        Thread thread = new Thread() {
            @Override
            public void run() {
                while (isPopupShowing) {
                    if (!popup.isShowing()) {
                        isPopupShowing = false;
                        MainActivity.this.runOnUiThread(new Runnable() {

                            public void run() {
                                loadDSP(type);
                            }
                        });
                    }
                }
            }
        };
        thread.start();
    }

但是这个线程将继续运行,直到弹出窗口被解除.所以我觉得用其他方式替换这个解决方案会更好.

我想要的是？当popup被解雇时,就像"popup is closed"这样的活动非常亲密.

为什么我这样用？我将在三个活动中使用此弹出窗口.这就是我为弹出窗口创建一个单独的类的原因.

任何帮助都会受到高度关注.

谢谢.

Answer 1

PopupWindow已经有了自己的dismiss监听器,只需按如下方式使用它

Popup popup = new Popup(getBaseContext());
popup.show(arg1);

改为

Popup popup = new Popup(getBaseContext());

popup.setOnDismissListener(new PopupWindow.OnDismissListener() {
            @Override
            public void onDismiss() {
                // Do your action
            }
        });

popup.show(arg1);