jQuery DataTables - 获取给定行的页面

Question

我有一个dataTable,包含数百个带有固定50 iDisplayLength选项的项目.我需要能够找到加载节点中特定行的页面.

我所管理的只是获取位置,遗憾的是内部行位置与当前排序和过滤的行索引不对应.

以jsFiddle为例.我可以检索位置或行#tr4(位置3),但我需要的iDisplayStart是2.

<table id="example">
      <thead>
          <tr>
            <th>ID</th>
            <th>Rendering engine</th>
            <th>Browser</th>
            <th>Platform(s)</th>
            <th>Engine version</th>
            <th>CSS grade</th>
          </tr>
        </thead>
        <tbody>
          <tr id="tr1" class="odd gradeX">
            <td>1</td>
            <td>Trident</td>
            <td>Internet Explorer 4.0</td>
            <td>Win 95+</td>
            <td class="center"> 4</td>
            <td class="center">X</td>
          </tr>
          <tr id="tr2" class="even gradeC">
            <td>2</td>
            <td>Trident</td>
            <td>Internet Explorer 5.0</td>
            <td>Win 95+</td>
            <td class="center">5</td>
            <td class="center">C</td>
          </tr>
          <tr id="tr3" class="odd gradeA">
            <td>3</td>
            <td>Trident</td>
            <td>Internet Explorer 5.5</td>
            <td>Win 95+</td>
            <td class="center">5.5</td>
            <td class="center">A</td>
          </tr>
          <tr id="tr4" class="even gradeA">
            <td>4</td>
            <td>Trident</td>
            <td>Internet Explorer 6</td>
            <td>Win 98+</td>
            <td class="center">6</td>
            <td class="center">A</td>
          </tr>
          <tr id="tr5" class="odd gradeA">
            <td>5</td>
            <td>Trident</td>
            <td>Internet Explorer 7</td>
            <td>Win XP SP2+</td>
            <td class="center">7</td>
            <td class="center">A</td>
          </tr>
    </tbody>
</table>

var oTable = $("#example").dataTable({
    "sDom": '<"clear">rtip<"clear">',
    "bPaginate": true,
    "iDisplayLength": 2,
});

var row = $(oTable.fnGetNodes()).filter("#tr4");
console.log(row[0]);

var position = oTable.fnGetPosition(row[0]);
console.log(position);

console.log(oTable.fnSettings()._iDisplayStart);;

// position is 3 but the page displayStart I need is 2.

Answer 1

我最终为它编写了一个小的dataTable插件:

// get the page of a given item in order to paginate to it's page on load
$.fn.dataTableExt.oApi.fnGetPageOfRow = function (oSettings, iRow) {
    // get the displayLength being used
    var displayLength = oSettings._iDisplayLength;

    // get the array of nodes, sorted (default) and using current filters in place for all pages (default)
    // see http://datatables.net/docs/DataTables/1.9.beta.1/DataTable.html#%24_details for more detals
    var taskListItems = this.$("tr", { "filter": "applied" });

    // if there's more than one page continue, else do nothing
    if (taskListItems.length <= displayLength) return;

    // get the index of the row inside that sorted/filtered array
    var index = taskListItems.index(iRow);

    // get the page by removing the decimals
    var page = Math.floor(index / displayLength);

    // paginate to that page 
    this.fnPageChange(page);
};

传入iRow,它将分页到该项目的页面.