C String数组的数组

Question

我将在C中的数组中存储字符串数组.

例如

{
{"hello", "world"},
{"my", "name", "is"},
{"i'm", "beginner", "point", "makes"}
}

我想存储以上数据.

我试着用

char *arr1 = {"hello", "world"};
char *arr2 = {"my", "name", "is"};
char *arr3 = {"i'm", "beginner", "point", "makes"}

但我不知道如何将这些数组存储在一个数组中.

提前致谢.

PS.

如何打印所有元素？

const char **arr[] = {arr1, arr2, arr3};

Answer 1

如果你想要一个char**数组,只需:

const char *arr1[] = {"hello", "world", NULL};
const char *arr2[] = {"my", "name", "is", NULL};
const char *arr3[] = {"i'm", "beginner", "point", "makes", NULL};

const char **arr[] = {arr1, arr2, arr3, NULL};

请注意,NULL终结符用于跟踪不同数组的大小,就像以NULL结尾的字符串一样.

int i, j;
for(i = 0; arr[i] != NULL; ++i) {
    for(j = 0; arr[i][j] != NULL; ++j) {
        printf("%s ", arr[i][j]);
    }
    printf("\n");
}

哪个输出:

hello world
my name is
i'm beginner point makes

Answer 2

与我最初的评估不同,它可以使用单个文字来完成.

#include <stdio.h>

int main()
{
    char* arr[3][4] = {
      {"hello", "world"},
      {"my", "name", "is"},
      {"i'm", "beginner", "point", "makes"}
    };

    printf ("%s", arr[2][3]);
    return 0;
}

数组1和2将在末尾用零填充为长度为4.

输出:

品牌

在这里测试:http://ideone.com/yDbUuz