如何在编辑表单中使用DoctrineModule\Validator\NoObjectExists - Zend Framework 2和Doctrine 2

Sre*_*ath 4 php validation zend-form doctrine-orm zend-framework2

DoctrineModule\Validator\NoObjectExists在用于编辑的Zend表单中使用验证器的最有效方法是什么?因为当我使用相同的Form保存编辑的值时,这将验证Object存在并且flags表单无效.

edi*_*igu 6

几周前,我在自定义过滤器中使用辅助方法解决了同样的问题.我不确定这是否是正确的方法,但它的工作原理.

  1. 编写自定义inputfilter扩展Zend\InputFilter\InputFilter.
  2. 在过滤init()方法中添加通用过滤器和验证器.
  3. 在输入过滤器中编写一个辅助方法,将doctrine的存在验证器附加到当前验证器链,如下所示.
  4. 在创建新对象时将存在验证器添加到过滤器实例,在编辑时使用通用过滤器实例.

所以,

<?php
/**
 * Baz filter
 */
class BazFilter extends Zend\InputFilter\InputFilter
{

/**
 * This method will be triggered automatically when you retrive baz filter via inputfiltermanager.
 */
public function init() 
{
    // Define your input names, types, validators and filters as arrays
    $this->add(array(
        'name' => 'code',
        'required' => true,
        'validators' => array(),
        'filters' => array()
    ));

    $this->add( array(...) );
    $this->add( array(...) );
    // ...
}

/**
 * Appends doctrine's noobjectexists validator to validator chain only when required.
 * 
 * @access public
 * @param \Doctrine\ORM\EntityRepository $repository
 * @return \Zend\InputFilter\InputFilter
 */
public function appendExistenceValidator(\Doctrine\ORM\EntityRepository $repository)
{
     $validatorSignature = array(
        'name' => 'code',
        'validators' => array(
            array(
                'name' => 'DoctrineModule\Validator\NoObjectExists',
                'options' => array(
                    'object_repository' => $repository,
                    'fields' => 'code',
                    'messages' => array( NoObjectExists::ERROR_OBJECT_FOUND => "This object with code already exists in database." )
                )
            )
        )
    );
    $validator = $this->getFactory()->createInput( $validatorSignature );
    $this->add($validator);
    return $this;
    }
}
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最后,在编辑时将此inputfilter附加到表单:

// $form = your form instance
// $filter = Bazfilter instance
$form->setData($postData)->setInputFilter( $filter );
if( $form->isValid() === false ) {
    // ...
}
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创建时:

// $filter = bazfilter instance
$repository = $entityManager->getRepository('Your\Entity\Name');
$filter->appendExistenceValidator( $repository ); // <-- Notice this line

$form->setData($postData)->setInputFilter( $filter );
if( $form->isValid() === false ) {
    // ...
}
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  • 所以,既然你编辑即用户,你可以给他,即一个已经存在的电子邮件...... (2认同)