在unix中获取2种模式之间的所有内容

Question

我需要一个awk/cut one liner来获取模式和最后一个文件名之间的所有内容,例如:

$ cat .exportfiles.text
/branches/WP_Fix/Code/SharedApp/src/gov/illinois/ies/business/rules/ed/CorticonFinIncomeEntiyLoader.java
/branches/WP_Fix/Code/BEAN/Framework/ejbModule/gov/illinois/ies/business/rules/entities/fin/Income.java
/branches/WP_Fix/settings/Environment/RT/properties/build.properties
/branches/WP_Fix/test/Environment/DEV/properties/build.properties

期望的输出:

Code/SharedApp/src/gov/illinois/ies/business/rules/ed
Code/BEAN/Framework/ejbModule/gov/illinois/ies/business/rules/entities/fin
settings/Environment/RT/properties
test/Environment/DEV/properties

Answer 1

sed -e 's,/branches/WP_Fix/\(.*\)/.*,\1,' < exportfiles.text