如何让一个线程不冻结整个JFrame.JAVA

Question

嘿,我只需要一个问题解答...我如何使以下代码不冻结我的整个JFrame？

                try {
                Thread.sleep(Integer.parseInt(delayField.getText()) * 1000);
                System.out.println("Hello!");
            } catch(InterruptedException ex) {
                Thread.currentThread().interrupt();
            }

Answer 1

使用不同的线程来执行此任务.如果你在主UI线程中执行此操作,那么它将冻结..例如,您可以执行以下操作

  new Thread() {

        @Override
        public void run() {
            try {
                Thread.sleep(Integer.parseInt(delayField.getText()) * 1000);
                System.out.println("Hello!");
            } catch (InterruptedException ex) {
                Thread.currentThread().interrupt();
            }

        }
    }.start();

UPDATE

在罗宾和马可的明智建议之后,我正在用更好的解决方案更新答案.

    ActionListener taskPerformer = new ActionListener() {
        public void actionPerformed(ActionEvent evt) {
                System.out.println("Hello!");

        }
    };
    javax.swing.Timer t = new javax.swing.Timer(Integer.parseInt(delayField.getText()) * 1000, taskPerformer);
    t.setRepeats(false);
    t.start();