从Typescript中的声明接口扩展一个类

Question

有没有办法处理类型脚本声明文件(如类)中的接口或变量,以便能够从中扩展类？

像这样:

declare module "tedious" {

   import events = module('events');

   export class Request extends event.EventEmitter {
       constructor (sql: string, callback: Function);
       addParameter(name: string, type: any, value: string):any;
       addOutputParameter(name: string, type: any): any;
       sql:string;
       callback: Function;
   };

}

现在我必须像这样重新定义EventEmitter接口并使用我自己的EventEmitter声明.

import events = module('events');

class EventEmitter implements events.NodeEventEmitter{
    addListener(event: string, listener: Function);
    on(event: string, listener: Function): any;
    once(event: string, listener: Function): void;
    removeListener(event: string, listener: Function): void;
    removeAllListener(event: string): void;
    setMaxListeners(n: number): void;
    listeners(event: string): { Function; }[];
    emit(event: string, arg1?: any, arg2?: any): void;
}

export class Request extends EventEmitter {
    constructor (sql: string, callback: Function);
    addParameter(name: string, type: any, value: string):any;
    addOutputParameter(name: string, type: any): any;
    sql:string;
    callback: Function;
};

稍后在我的TypeScript文件中扩展它

import tedious = module('tedious');

class Request extends tedious.Request {
   private _myVar:string; 
   constructor(sql: string, callback: Function){
       super(sql, callback);
   }
}

Answer 1

我不知道 2013 年的情况，但现在很简单：

/// <reference path="../typings/node/node.d.ts" />
import * as events from "events";

class foo extends events.EventEmitter  {
   constructor() {
      super();
   }

   someFunc() { 
      this.emit('doorbell');
   }
}

我一直在寻找这个问题的答案，最后终于找到了答案。