Rob*_*tex 1 python yield generator tornado
我使用yield和task来异步获取四个jsons:
@gen.engine
def get_user_data(self, sn, snid, fast_withdrawals):
end_timestamp = time.time()
start_timestamp = end_timestamp - CONFIG.LOYALITY_LEVELS.PERIOD
active_apps_response, total_payments_response, payments_for_period_response, withdrawals_response = yield [
gen.Task(self.http_client.fetch, self.__get_active_apps_url(sn, snid)), gen.Task(self.http_client.fetch, self.__get_total_payments_url(sn, snid)),
gen.Task(self.http_client.fetch, self.__get_payments_sum_for_period_url(sn, snid, start_timestamp, end_timestamp)),
gen.Task(self.http_client.fetch, self.__get_total_withdrawals_url(sn, snid, fast_withdrawals))
]
active_apps = self.__active_apps_handler(active_apps_response)
total_payments = self.__get_total_payments_handler(total_payments_response)
payments_for_period = self.__payments_sum_for_period_handler(payments_for_period_response)
withdrawals = self.__get_total_withdrawals_handler(withdrawals_response)
yield gen.Return(active_apps, total_payments, payments_for_period, withdrawals)
Run Code Online (Sandbox Code Playgroud)
但是如果我使用yield而不是返回上层函数也变成了生成器而且我也不能使用return.那么,如何在没有调用函数生成器的情况下从龙卷风函数返回结果呢?我正在使用Python 2.7
您不能同时返回值和屈服值.当您产生值时,函数返回一个生成器 - 因此它已经返回了一个值,并且不能返回更多值.这样做根本没有意义.
您可以在return没有任何值的情况下调用以引发StopIteration异常并结束生成器,但返回值在生成器中从语义上没有意义.
如果你想有时候返回一个生成器,有时候返回一个值,用另一个返回一个生成器(通过调用这个函数创建)或者替代值来包装你的函数,虽然我不是这样的东西通常是坏的从设计的角度来看.