IOS上的Android帖子请求

Question

我正在尝试将Android应用程序移植到IOS平台.我从位于Apache Tomcat服务器中的服务获取数据,最近他们在服务上添加了安全性.安全概述是

1. https简单请求
2. if(valid_user) - > service返回数据
3. else-> service返回登录表单 - > post credentials-> service返回数据

Android版本没有问题.在添加安全性之前,我正在执行简单的http请求,但现在我需要使用我的凭据执行POST请求,因此我总是收到error.html.我远不是网络编程方面的专家.

这是Android http客户端设置代码:

if(httpClient==null)
{
 DefaultHttpClient client = new DefaultHttpClient();

 KeyStore trustStore = KeyStore.getInstance(KeyStore.getDefaultType());
 trustStore.load(null, null);
 SSLSocketFactory sf = new MySSLSocketFactory(trustStore);
 sf.setHostnameVerifier(SSLSocketFactory.ALLOW_ALL_HOSTNAME_VERIFIER);
 SchemeRegistry registry = new SchemeRegistry();
 registry.register(new Scheme("https", sf, 8443));

 mgr = new ThreadSafeClientConnManager(client.getParams(), registry);
 int timeoutConnection = 5000;
 HttpConnectionParams.setConnectionTimeout(client.getParams(), timeoutConnection);
 // Set the default socket timeout (SO_TIMEOUT) 
 // in milliseconds which is the timeout for waiting for data.
 int timeoutSocket = 7000;
 HttpConnectionParams.setSoTimeout(client.getParams(), timeoutSocket);
 httpClient = new DefaultHttpClient(mgr, client.getParams());
}

这是MySSLSocketFactory类:

public class MySSLSocketFactory extends SSLSocketFactory {
    SSLContext sslContext = SSLContext.getInstance("TLS");

    public MySSLSocketFactory(KeyStore truststore) throws NoSuchAlgorithmException, KeyManagementException, KeyStoreException, UnrecoverableKeyException {
        super(truststore);

        TrustManager tm = new X509TrustManager() {
            public void checkClientTrusted(X509Certificate[] chain, String authType) throws CertificateException {
            }

            public void checkServerTrusted(X509Certificate[] chain, String authType) throws CertificateException {
            }

            public X509Certificate[] getAcceptedIssuers() {
                return null;
            }
        };

        sslContext.init(null, new TrustManager[] { tm }, null);
    }

    @Override
    public Socket createSocket(Socket socket, String host, int port, boolean autoClose) throws IOException, UnknownHostException {
        return sslContext.getSocketFactory().createSocket(socket, host, port, autoClose);
    }

    @Override
    public Socket createSocket() throws IOException {
        return sslContext.getSocketFactory().createSocket();
    }
}

这是Android的POST请求代码(工作正常):

...
HttpPost httpost = new HttpPost(host+"/serviceName/j_security_check"); 
List<BasicNameValuePair> nvps = new ArrayList<BasicNameValuePair>();
nvps.add(new BasicNameValuePair("j_username", userName));
nvps.add(new BasicNameValuePair("j_password", userPassword));

try {
     httpost.setEntity(new UrlEncodedFormEntity(nvps, HTTP.UTF_8));
    } 
catch (UnsupportedEncodingException e) {
    // TODO Auto-generated catch block
                e.printStackTrace();
}

try {
     httpResponse = httpClient.execute(httpost);
} catch (ClientProtocolException e) {
      // TODO Auto-generated catch block
      e.printStackTrace();
} catch (IOException e) {
      // TODO Auto-generated catch block
      e.printStackTrace();
}
entity = httpResponse.getEntity();
...

我尝试了几种方法但总是有相同的结果.我只添加了我认为非凡的代码:

-(void)connection:(NSURLConnection *)connection willSendRequestForAuthenticationChallenge:(NSURLAuthenticationChallenge *)challenge
{
  NSURLCredential *credential=[NSURLCredential credentialWithUser:self.userName password:self.userpassword persistence:NSURLCredentialPersistenceForSession];
   [[challenge sender] useCredential:credential forAuthenticationChallenge:challenge];
}

在定义POST请求的方法中:

{
...
NSString *urlstr=[NSString stringWithFormat:@"%@%@",host,@"serviceName/j_security_check"];
NSURL *url=[[NSURL alloc]initWithString:urlstr];
NSMutableURLRequest *request=[NSMutableURLRequest requestWithURL:url];
NSString *params=[[NSString alloc]initWithFormat:@"j_username=my_userName&j_userpassword=my_userPassword"];
[request setHTTPMethod:@"POST"];
[request setHTTPBody:[params dataUsingEncoding:NSUTF8StringEncoding]];
[[NSURLConnection alloc]initWithRequest:request delegate:self];
}

我一直在网上搜索有效的POST请求,但没有一个是有用的...

如果您需要更多信息,请索取

你的帮助是折旧的.

编辑:我改变了willSendRequestForAuthenticationChallenge委托,因为使用前一个我没有得到login.html表单.

编辑:我从android添加了http客户端设置代码.现在发布数据的方法看起来类似于@MTahir答案,但我仍然得到error.html,这意味着(我认为)POST方法正常工作但数据没有以正确的方式编写.

Answer 1

如果您正在寻找一段可以发布数据的工作代码，那么试试这个，我已经使用了这个，它效果很好。

它需要在字典对象中发送数据。将要发送的数据编码为 POST，然后返回响应（如果您想要字符串格式的结果，可以在返回数据时使用 [[NSString alloc] initWithData:dresponse encoding: NSASCIIStringEncoding];）

-(NSData*) postData:(NSDictionary *) postDataDic{

NSData *dresponse = [[NSData alloc] init];

NSURL *nurl = [NSURL URLWithString:url];
NSDictionary *postDict = [[NSDictionary alloc] initWithDictionary:postDataDic];
NSData *postData = [self encodeDictionary:postDict];

// Create the request
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:nurl];
[request setHTTPMethod:@"POST"]; // define the method type
[request setValue:[NSString stringWithFormat:@"%d", postData.length] forHTTPHeaderField:@"Content-Length"];
[request setValue:@"application/x-www-form-urlencoded charset=utf-8" forHTTPHeaderField:@"Content-Type"];
[request setHTTPBody:postData];

    // Peform the request
    NSURLResponse *response;
    NSError *error = nil;

    dresponse = [NSURLConnection sendSynchronousRequest:request  
                                                 returningResponse:&response
                                                             error:&error];

return dresponse;
}

此方法为 POST 准备字典数据

  - (NSData*)encodeDictionary:(NSDictionary*)dictionary {
    NSMutableArray *parts = [[NSMutableArray alloc] init];
    for (NSString *key in dictionary) {
        NSString *encodedValue = [[dictionary objectForKey:key] stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
        NSString *encodedKey = [key stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]; 
        NSString *part = [NSString stringWithFormat: @"%@=%@", encodedKey, encodedValue];
        [parts addObject:part];
    }
    NSString *encodedDictionary = [parts componentsJoinedByString:@"&"];
    return [encodedDictionary dataUsingEncoding:NSUTF8StringEncoding];
}

如果您有任何困惑，请告诉我。