是否可以忽略异常？

Question

在Java中,是否可以创建一个throws不检查语句的方法.

例如:

public class TestClass {
    public static void throwAnException() throws Exception {
        throw new Exception();
    }
    public static void makeNullPointer() {
        Object o = null;
        o.equals(0);//NullPointerException
    }
    public static void exceptionTest() {
        makeNullPointer(); //The compiler allows me not to check this
        throwAnException(); //I'm forced to handle the exception, but I don't want to
    }
}

Answer 1

你可以尝试什么都不做:

public static void exceptionTest() {
    makeNullPointer(); //The compiler allows me not to check this
    try {
        throwAnException(); //I'm forced to handle the exception, but I don't want to
    } catch (Exception e) { /* do nothing */ }
}

请记住,在现实生活中,这是非常不明智的.这可以隐藏错误并让你整整一周都在寻找狗,而这个问题实际上是一只猫(ch)._{^{(来吧,至少放一个System.err.println()- 记录是最好的做法,正如@BaileyS所建议的那样.)}}

Java中未经检查的异常扩展了RuntimeException该类.投掷他们不会要求catch他们的客户:

// notice there's no "throws RuntimeException" at the signature of this method
public static void someMethodThatThrowsRuntimeException() /* no need for throws here */ {
    throw new RuntimeException();
}

扩展的类RuntimeException也不需要throws声明.

并从Oracle一句话吧:

这是底线指南:如果可以合理地期望客户端从异常中恢复,则将其作为已检查的异常.如果客户端无法执行任何操作以从异常中恢复,请将其设置为未经检查的异常.