Luc*_*ryn 4 java rest android uri mongodb
我收到一个错误:
W/System.err(32720): java.lang.IllegalArgumentException: Illegal character in query at index 89: https://api.mongolab.com/api/1/databases/activity_recognition/collections/entropy_data?f={%20mean0%22:%201}&apiKey=myApiKey
String apiURI = "https://api.mongolab.com/api/1/databases/activity_recognition/collections/entropy_data?f={%22mean0%22:%201}&apiKey=myApiKey";
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我尝试这样做-用%7B代替大括号:但这无济于事
https://api.mongolab.com/api/1/databases/activity_recognition/collections/entropy_data?f=%7B"mean0":%201%7D&apiKey=myApiKey
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任何人?
编辑:
String query = "https://api.mongolab.com/api/1/databases/activity_recognition/collections/entropy_data?f={\""+arrayName+"\":%201}&apiKey=myApiKey";
try {
query = URLEncoder.encode(query, "utf-8");
} catch (UnsupportedEncodingException e1) {
// TODO Auto-generated catch block
e1.printStackTrace();
}
String apiURI = query;
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没有帮助。现在我得到:
05-23 22:13:21.855: E/SendMail(12428): Target host must not be null, or set in parameters. scheme=null, host=null, path=https://api.mongolab.com/api/1/databases/activity_recognition/collections/entropy_data?f={"mean0":%201}&apiKey=myAPI
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如果我在查询的声明中将%20更改为空格,则会得到:
05-23 22:14:51.435: E/SendMail(13164): Target host must not be null, or set in parameters. scheme=null, host=null, path=https://api.mongolab.com/api/1/databases/activity_recognition/collections/entropy_data?f={"mean0":+1}&apiKey=myAPI
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另外,如果我不在中间使用arrayName字符串,而只是直接从浏览器使用字符串,效果是一样的!
从我所看到的情况来看,每次尝试要么遗漏某些东西,要么对其进行不应编码的内容(例如“?”),或者对某些内容进行双重编码,从而对url编码中的“%”进行url编码。
只编码您关心的转义位,并只进行一次编码怎么样?
String apiURI =
"https://api.mongolab.com/api/1/databases/activity_recognition/collections/entropy_data?f="
+ URLEncoder.encode("{\"mean0\": 1}", "UTF-8")
+ "&apiKey=myApiKey";
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如果要使用java.net.URI,则必须单独包含查询字符串,例如:
new URI(
"https",
"api.mongolab.com",
"/api/1/databases/activity_recognition/collections/entropy_data",
"f={\"mean0\": 1}&apiKey=myApiKey",
null
).toURL()
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