与jquery ajax序列化的模型绑定无法正常工作

Question

我有以下型号:

public class RegisterUseraccount
{
    [Required]
    [DataType(DataType.EmailAddress)]
    [Display(Name = "E-Mail-Adresse")]
    public string Email { get; set; }

    [Required]
    [Display(Name = "Vorname")]
    public string FirstName { get; set; }

    [Required]
    [Display(Name = "Nachname")]
    public string LastName { get; set; }

    [Required]
    [DataType(DataType.Password)]
    [MinLength(5)]
    [Display(Name = "Passwort")]
    public string Password { get; set; }

    ...
}

以下观点:

@using (Html.BeginForm("Register", "Useraccount", FormMethod.Post, new { id = "registerUseraccountForm", @class = "ym-form" }))
{
    @Html.ValidationSummary(true)        

    <div class="ym-grid">
        <div class="ym-g50 ym-gl">
            <div class="ym-fbox-text">
                @Html.LabelForRequired(model => model.RegisterUseraccount.FirstName, null)               
                @Html.EditorFor(model => model.RegisterUseraccount.FirstName, new { required = "required", name = "firstName" })
                @Html.ValidationMessageFor(model => model.RegisterUseraccount.FirstName)                  
            </div>
        </div>
    ...

和我的JavaScript

function sendForm(target) {
    alert(data);
    $.ajax({
        url: target,
        type: "POST",
        contentType: 'application/json',
        data: $("#registerUseraccountForm").serialize(),
        success: ajaxOnSuccess,
        error: function (jqXHR, exception) {
            alert('Error message.');
        }
    });

这是序列化的结果:

RegisterUseraccount.FirstName=Peter&RegisterUseraccount.LastName=Miller&RegisterUseraccount.Email=miller%40gmail.com&RegisterUseraccount.Password=admin

这是我试图POST到的控制器方法:

[HttpPost]
public ActionResult Register(RegisterUseraccount registerUseraccount)
{
    ...
}

...但是数据没有到达方法,我收到错误404.我认为模型绑定器无法工作.

有效的是使用名称firstName = Peter发送的数据,但实际发送的是RegisterUseraccount.FirstName = Peter.

我该如何处理这个问题？

Answer 1

删除contentType: 'application/json',并修改它以更好(从我的角度来看)

$('#registerUseraccountForm').submit(function () {
    if ($(this).valid()) {
        $.ajax({
            url: this.action,
            type: this.method,
            data: $(this).serialize(),
            beforeSend: function () {

            },
            complete: function () {

            },
            ...