如何将ItemsControl.ItemsSource与XAML中的属性绑定？

Question

我有一个简单的窗口:

<Window x:Class="WinActivityManager"
        xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
        xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml">
    <Grid>
        <ListView x:Name="lvItems" />
    </Grid>
</Window>

以及相关代码背后:

public partial class WinActivityManager : Window
{
    private ObservableCollection<Activity> Activities { get; set; }

    public WinActivityManager()
    {
        Activities = new ObservableCollection<Activity>();
        InitializeComponent();
    }

    // Other code ...
}

如果我在窗口构造函数中编写以下绑定:

lvItems.ItemsSource = Activities;

然后当我添加或删除元素时,我的ListView会自动更新Activities.

我该如何在XAML中编写绑定？
我试过这个,但它不起作用:

<ListView x:Name="lvItems" ItemsSource="{Binding=Activities}" />

如何在XAML中完成这项工作？

Answer 1

@JesseJames说的是真的,但还不够.

你必须把

private ObservableCollection<Activity> Activities { get; set; } 

如

public ObservableCollection<Activity> Activities { get; set; }

绑定应该是:

<ListView x:Name="lvItems" ItemsSource="{Binding Path=Activities}" />

问候,

Answer 2

您必须设置的DataContext到这个像人回答了,但您可以设置DataContext通过xaml也:

<Window x:Class="WinActivityManager"
        xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
        xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
        DataContext="{Binding RelativeSource={RelativeSource Self}}">
    <Grid>
        <ListView x:Name="lvItems" ItemsSource="{Binding Path=Activities}" />
    </Grid>
</Window>