计算两个1D线段的重叠距离

Question

尝试构建一个函数,该函数将返回2个线段之间的总重叠距离,由start和end int表示.

目前我有这个:我在某个地方上网,

def overlap(min1, max1, min2, max2):
    """returns the overlap between two lines that are 1D"""
    result = None
    if min1 >= max2 or min2 >= max1: result =  0
    elif min1 <= min2:
        result = max1 - min2
    else: result = max2 - min1
    return result

这适用于0 100,0,20的情况,它返回100.这显然是错误的.有一种简单的计算方法可以返回正确的值吗？

Answer 1

def overlap(min1, max1, min2, max2):
    return max(0, min(max1, max2) - max(min1, min2))

>>> overlap(0, 10, 80, 90)
0
>>> overlap(0, 50, 40, 90)
10
>>> overlap(0, 50, 40, 45)
5
>>> overlap(0, 100, 0, 20)
20

Answer 2

尚未完全测试,但如何 -

def overlap(min1,max1,min2,max2):
    start = max(min1,min2)
    end = min(max1,max2)
    d = end - start
    if d < 0:
        return 0
    else:
        return d

#some tests
print overlap(0,100,0,20)
print overlap(5,10,15,20)
print overlap(1,3,0,5)
print overlap(-5,5,-2,10)

>>> 
20
0
2
7