PHP echo SQL Count

Question

好的,所以我遇到了问题.我似乎无法在PHP中成功回显SQL Count.

SQL:

SELECT TableA.C, COUNT(*) FROM TableA JOIN TableB ON (TableA.C = TableB.D) 
   WHERE TableB.E = 1 GROUP BY TableA.C ORDER BY COUNT(*) DESC

PHP:

$result= mysql_query("SELECT TableA.C, COUNT(*) FROM TableA JOIN TableB ON (TableA.C = TableB.D) 
   WHERE TableB.E = 1 GROUP BY TableA.C ORDER BY COUNT(*) DESC");

while($rows = mysql_fetch_array($result))
{
     echo $rows['Count']."</br>";
}
$rows = mysql_fetch_array($result);
{
     echo $rows['Count'];
}

我尝试了两种我在网上找到的不同的东西(上面).我甚至尝试过使用"mysql_fetch_array($ result,MYSQL_ASSOC)"而不仅仅是mysql_fetch_array($ result).

每次,我都会收到相同的错误消息:

Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in 

/home/semsemx1/public_html/x/xx.php

另外,我试过大写" $rows['COUNT']",但这不起作用.

任何帮助,将不胜感激.

Answer 1

你只需要计算一下 ALIAS

SELECT TableA.C, COUNT(*) as total

然后你可以用它来调用它

echo $rows['total']

然后我希望你记住mysql_*函数已被弃用,所以我建议你切换到mysqli或PDO