KRP*_*KRP 6 .net c# dynamic expandoobject c#-4.0
我需要输入将动态xml转换为定义的c#对象模型
我的样本xml如下:
<?xml version="1.0" encoding="utf-8" ?>
<Persons>
<Person>
<Id>10</Id>
<FirstName> Dino </FirstName>
<LastName> Esposito </LastName>
<Addresses>
<Address>
<AddressType>BillTo</AddressType>
<Street1></Street1>
<Street2></Street2>
<Street3></Street3>
<City>Moscow</City>
</Address>
<Address>
<AddressType>ShipTo</AddressType>
<Street1></Street1>
<Street2></Street2>
<Street3></Street3>
<City>Moscow</City>
</Address>
<Address>
<AddressType>Contact</AddressType>
<Street1></Street1>
<Street2></Street2>
<Street3></Street3>
<City>Moscow</City>
</Address>
</Addresses>
</Person>
</Persons>
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我希望在运行时将此xml的值转换为C#对象.我希望定义一个类似于下面的对象:我的预期类对象C#如下:
public class Person
{
public int Id { get; set; }
public String FirstName { get; set; }
public String LastName { get; set; }
public IList<Address> Addresses { get; set; }
}
public class Address
{
public string AddressType { get; set; }
public string Street1 { get; set; }
public string Street2 { get; set; }
public string Street3 { get; set; }
public string City { get; set; }
}
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我在C#4.0中经历了动态和ExpandoObject,这种方法允许我通过使用键动态获取值.我不知道如何将这些填充到我的数据模型中.
注意:我不想定义这个类模型结构,这会在一段时间内不断变化.我正在寻找一个解决方案,它允许我获取像DynamicObject.Addresses.Address [0] .City这样的值.
请提供您的意见.
使用LINQ2XML的解决方案可能如下所示(不需要类):
var xml = XDocument.Parse(xmlSrc); // from XML string, e.g.: <xml ...><Persons><Person>...
//var xml = XDocument.Load(xmlFile); // from XML file, e.g.: c:\temp\persons.xml
var persons = xml.Root.Elements("Person").ToList();
var p1Addresses = persons[0].Elements("Addresses").ToList();
foreach (var address in p1Addresses.Elements("Address"))
{
var elementAddress = address.Element("AddressType");
var elementCity = address.Element("City");
System.Console.WriteLine(string.Format("{0} - {1}", elementAddress.Value, elementCity.Value));
}
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输出是:
BillTo - Moscow
ShipTo - Moscow
Contact - Moscow
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检查这个例子:
string xml =
@"<?xml version='1.0' encoding='utf-8' ?>
<Persons>
<Person>
<Id>10</Id>
<FirstName> Dino </FirstName>
<LastName> Esposito </LastName>
<Addresses>
<Address>
<AddressType>BillTo</AddressType>
<Street1></Street1>
<Street2></Street2>
<Street3></Street3>
<City>Moscow</City>
</Address>
<Address>
<AddressType>ShipTo</AddressType>
<Street1></Street1>
<Street2></Street2>
<Street3></Street3>
<City>Moscow</City>
</Address>
<Address>
<AddressType>Contact</AddressType>
<Street1></Street1>
<Street2></Street2>
<Street3></Street3>
<City>Moscow</City>
</Address>
</Addresses>
</Person>
</Persons>";
XElement root = XElement.Parse(xml);
IEnumerable<XElement> list = root.XPathSelectElements("./Person/Addresses/Address[2]/City");
foreach (XElement el in list)
Console.WriteLine(el);
Console.ReadLine();
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你会得到:<City>Moscow</City>
或者使用以下命令查看此解决方案DynamicObject
:
XElement root = XElement.Parse(xml);
dynamic persons = DynamicXml.Parse(xml);
Console.WriteLine(persons.Person.Addresses.Address[1].City);
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