first_or_create通过电子邮件,然后保存嵌套模型

che*_*ell 8 ruby ruby-on-rails nested-attributes ruby-on-rails-3.2

我两个型号UserSubmission如下:

class User < ActiveRecord::Base
  # Associations
  has_many :submissions
  accepts_nested_attributes_for :submissions

  # Setup accessible (or protected) attributes for your model
  attr_accessible :email, :name, :role, :submission_ids, :quotation_ids, :submissions_attributes

  validates :email, :presence => {:message => "Please enter a valid email address" }
  validates :email, :uniqueness => { :case_sensitive => false }
end

class Submission < ActiveRecord::Base
  belongs_to :user
  attr_accessible :due_date, :text, :title, :word_count, :work_type, :rush, :user, :notes

  validates :work_type, :title, :text,:presence => true
  validates :text, :length => { :minimum => 250 }
  validates :word_count, :numericality => { :only_integer => true }
end
Run Code Online (Sandbox Code Playgroud)

我有一个表格,收集这两个模型所需的数据.用户控制器:

def index
  @user = User.new
  @user.submissions.build
end

def create
  @user = User.where(:email => params[:user][:email]).first_or_create(params[:user])

  if @user
    redirect_to :root
  else
    render 'pages/index'
  end
end
Run Code Online (Sandbox Code Playgroud)

我想要做的是首先通过提交的电子邮件检查用户是否已经存在于系统中.如果是,那么我想为该用户创建提交.否则,请同时创建用户和提交.

我对如何使用该first_or_create方法做到这一点很困惑.

任何帮助赞赏.

Sub*_*has 13

first_or_create 接受一个块.所以你可以这样做:

@user = User.where(:email => params[:user][:email]).first_or_create do |user|
  # This block is called with a new user object with only :email set
  # Customize this object to your will
  user.attributes = params[:user]
  # After this, first_or_create will call user.create, so you don't have to
end
Run Code Online (Sandbox Code Playgroud)