解决表圆角CSS

Question

我有圆角的CSS规则:

th, td { padding: 8px;
         background: #E8ECE0;
         text-align: center;
         border: 1px solid #444;
         border-bottom-width: 0px;
}
thead { background-color: #446bb3  ; color :#fff; padding:4px; line-height:30px }
tbody tr:nth-child(even) {background: #F6F6EC;}
tbody tr:nth-child(odd) {background: #FFF}

tr:first-child td, tr:first-child th {
    border-top-left-radius: 12px; border-top-right-radius: 12px;
}
tr:last-child td {
    border-bottom: 1px solid #444;
    border-bottom-left-radius: 12px; border-bottom-right-radius: 12px;
}
table { border-spacing: 0; border: 0; margin:0px; width:100%; padding:5px}
td.pd {border-bottom-left-radius: 12px; border-bottom-right-radius: 12px;}
td.pu {border-top-left-radius: 12px; border-top-right-radius: 12px;}

我的html表是:

<table >
    <tbody>
      <tr >
        <td >Hello</td><td >Hello</td>
      </tr>
      <tr >
         <td >Hello</td><td >Hello</td>
      </tr>
      <tr >
         <td >Hello</td><td >Hello</td>
      </tr>
      <tr >
      <td >Hello</td><td >Hello</td>
      </tr>
    </tbody>
  </table>

这给了我这个

我如何解决这个问题,因为表格和表格中间的td元素也有圆角？我只需要第一行和最后一行有圆角.

Answer 1

假设你table的html类似于以下内容:

<table>
    <thead>
        <tr>
            <th>First column</th>
            <th>Second column</th>
        </tr>
    </thead>
    <tbody>
        <tr>
            <td>Row one, cell one</td>
            <td>Row one, cell two</td>
        </tr>
        <tr>
            <td>Row two, cell one</td>
            <td>Row two, cell two</td>
        </tr>
        <tr>
            <td>Row three, cell one</td>
            <td>Row four, cell two</td>
        </tr>
    </tbody>
</table>

以下CSS应该有效:

table {
    border-spacing: 0;
}
th, td {
    border: 1px solid #000;
    padding: 0.5em 1em;
}
/* the first 'th' within the first 'tr' of the 'thead': */
thead tr:first-child th:first-child {
    border-radius: 0.6em 0 0 0;
}
/* the last 'th' within the first 'tr' of the 'thead': */
thead tr:first-child th:last-child {
    border-radius: 0 0.6em 0 0;
}
/* the first 'td' within the last 'tr' of the 'tbody': */
tbody tr:last-child td:first-child {
    border-radius: 0 0 0 0.6em;
}
/* the last 'td' within the last 'tr' of the 'tbody': */
tbody tr:last-child td:last-child {
    border-radius: 0 0 0.6em 0;
}

JS小提琴演示.

编辑回应OP提出的问题:

表中的边界有点想,我怎么做它1px

单元格之间的边界有点厚,因为一个单元格的左边框与前一个单元格的右边框相对(顶部/底部边框相同).

删除该效果的一种方法是border-collapse: collapse;在table元素上指定.不幸的是这样做的效果是也删除/复位/重载border-radius声明:演示.

更复杂的方法是手动删除具有前一行的行的顶部边框,以及跟随单元格的单元格的左边框,将以下内容添加到先前的CSS:

thead + tbody tr td,
tr + tr td {
    border-top: 0;
}

tr th + th,
tr td + td {
    border-left: 0;
}

JS小提琴演示.

编辑减少使CSS更耐用(对于单细胞行,添加tfoot或删除thead):

table {
    border-spacing: 0;
}
th, td {
    border: 1px solid #000;
    padding: 0.5em 1em;
}
thead tr:first-child th:first-child,
tbody:first-child tr:first-child td:first-child {
    border-top-left-radius: 0.6em;
}
thead tr:first-child th:last-child,
tbody:first-child tr:first-child td:last-child {
    border-top-right-radius: 0.6em;
}

thead + tbody tr:last-child td:first-child,
tfoot tr:last-child td:first-child {
    border-bottom-left-radius: 0.6em;
}
thead + tbody tr:last-child td:last-child,
tfoot tr:last-child td:last-child {
    border-bottom-right-radius: 0.6em;
}

thead + tbody tr td,
tfoot + tbody tr td,
tfoot tr td,
tbody + tbody tr td,
tr + tr td {
    border-top: 0;
}

tr th + th,
tr td + td {
    border-left: 0;
}

JS小提琴演示.

tbody在没有元素的情况下,存在多个元素的问题,tfoot其中第一个元素tbody将在其下边界处保留边界半径.

Answer 2

你可以把表放入div.div的样式(示例):

div {
  border-radius: 4px;
  -moz-border-radius: 4px
  -webkit-border-radius: 4px;
  overflow: hidden; /*notice*/
}

因此桌角将被隐藏.