如何解决以下编译器错误:
xstddef(180): error C2678: binary '<' : no operator found which takes a left-hand operand of type 'const std::string' (or there is no acceptable conversion)
tuple(572): could be 'bool std::operator <(const std::tuple<> &,const std::tuple<> &)'
while trying to match the argument list '(const std::string, const std::string)'
xstddef(179) : while compiling class template member function 'bool std::less<_Ty>::operator ()(const _Ty &,const _Ty &) const'
with
[
_Ty=std::string
]
map(177) : see reference to function template instantiation 'bool std::less<_Ty>::operator ()(const _Ty &,const _Ty &) const' being compiled
with
[
_Ty=std::string
]
type_traits(743) : see reference to class template instantiation 'std::less<_Ty>' being compiled
with
[
_Ty=std::string
]
xtree(1028) : see reference to class template instantiation 'std::is_empty<_Ty>' being compiled
with
[
_Ty=std::less<std::string>
]
map(67) : see reference to class template instantiation 'std::_Tree<_Traits>' being compiled
with
[
_Traits=std::_Tmap_traits<std::string,IDispatcherPtr,std::less<std::string>,std::allocator<std::pair<const std::string,IDispatcherPtr>>,false>
]
main.cpp(506) : see reference to class template instantiation 'std::map<_Kty,_Ty>' being compiled
with
[
_Kty=std::string,
_Ty=IDispatcherPtr
]
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对于以下代码:
class IDispatcher
{
virtual void operator()() = 0;
};
class AlarmDispatcher: public IDispatcher
{
virtual void operator()()
{
}
};
typedef boost::shared_ptr<IDispatcher> IDispatcherPtr;
int main()
{
std::map<std::string, IDispatcherPtr> dispatchers;
dispatchers["alarm"] = boost::make_shared<AlarmDispatcher>();
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第一个问题:
您应该明确包含所有必需的标头,而不是通过包含其他标头间接包含它们:
#include <string> // <== IN PARTICULAR THIS ONE
#include <map>
#include <boost/shared_ptr.hpp>
#include <boost/make_shared.hpp>
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从评论来看,似乎你包括<string.h>标题(它是标准C库标题)而不是<string>标题,这std::string是定义类的位置.
第二个问题:
您忘记在类之间建立继承关系:
class AlarmDispatcher : public IDispatcher
// ^^^^^^^^
{
virtual void operator()()
{
}
};
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