PHP-使用CURL将图像文件上传到其他域

Question

我有两个域，例如site1.loc和site2.loc。在site1.loc中，我有一个php表单文件，如下所示：

<?php
$c_name = "";
$c_phone = "";

if($_SERVER['REQUEST_METHOD']=="POST"){

    $c_name = $_POST['c_name'];
    $c_phone = $_POST['c_phone'];
    $c_pic = $_FILES['c_pic']['name']; // Image file

        // submit target URL
        $url = 'http://site2.loc/handler.php';

        $fields = array(
           'field1'=>$c_name,
           'field2'=>$c_phone,
           'field3'=>$c_pic
        );

        $postvars='';
        $sep='';
        foreach($fields as $key=>$value) 
        { 
           $postvars.= $sep.urlencode($key).'='.urlencode($value); 
           $sep='&'; 
        }


        //open connection
        $ch = curl_init();

        //set the url, number of POST vars, POST data
        curl_setopt($ch,CURLOPT_URL,$url);
        curl_setopt($ch,CURLOPT_POST,count($fields));
        curl_setopt($ch,CURLOPT_POSTFIELDS,$postvars);

        //execute post
        $result = curl_exec($ch);

        if(curl_errno($ch)) {
            echo 'Error: ' . curl_error($ch);
        }
        else {
            echo $result;
        }

        //close connection
        curl_close($ch);

}


echo '
<form action="" method="post" enctype="multipart/form-data">
    Name : <input type="text" name="c_name" value="'.$c_name.'" /> <br />
    Phone : <input type="text" name="c_phone" value="'.$c_phone.'" /> <br />
    Image : <input type="file" name="c_pic" /> <br />
    <input type="submit" />
</form>
    ';
?>

和handler.php在site2.loc这样的：

<?php
ob_start();
if (!isset($_SESSION)) { session_start(); }

    // CONNECT TO DB
    $db_con = mysql_connect("localhost", "root", "root");// or die("Could not connect to db.");
    if(!mysql_select_db("site2",$db_con)) die("No database selected.");

    // POST
    if(isset($_POST)){
        $c_name = $_POST['field1'];
        $c_phone = $_POST['field2'];    
        $c_pic = $_POST['field3'];  

        // UPLOAD FILE
        /* UPLOAD IMAGE CODE HERE */

        // INSERT TO DB
        if(mysql_query("INSERT INTO kontak (nama, telpon) VALUES ('$c_name','$c_phone')")){
            echo "INSERT SUCCESS";
        } else {
            echo "INSERT FAILED";
        }
    }

?>

该脚本可以很好地运行以将数据存储到数据库，但不能用于上传图像文件。有人可以帮我修改上面的脚本以上传图像文件吗？

之前谢谢。

Answer 1

此答案中没有代码，只是一个将绕过的工作流程示例curl：

1. 用户通常将带有上传文件的表单发布到“站点1”。
2. “站点1”处理表单和上载的文件。该文件放置在可通过Web访问的临时目录中。
3. 在“站点1”上，一旦检查了上载的文件，就file_get_contents('http://site2.loc/pullfile.php?f=filename&sec=checkcode')拨打电话。的内容就是pullfile.php这样做的，将文件从“站点1”拉到“站点2”。
4. 从返回file_get_contents()可以从“网站2”返回错误检查pullfile.php和错误，处理它。没错，删除临时文件。
5. 该&sec=checkcode可用于确认文件已经成功上传至“网站2”。它可能是文件的MD5或您提出的其他内容。

只是一个主意。

编辑：一些示例代码可以使事情变得更清晰，也许：]

// ---- Site 1, formprocess.php ----

// Your form processing goes here, including
// saving the uploaded file to a temp dir.

// Once the uploaded file is checked for errors, 
// you need move it to a known temp folder called 
// 'tmp'.

// this is the uploaded file name (which you would
// have got from the processed form data in $_FILES
// For this sample code, it is simple hard-coded.
$site1File = 'test.jpg';

$site1FileMd5 = md5_file('./tmp/'.$site1File);

// now make a remote request to "site 2"
$site2Result = file_get_contents('http://'.SITE_2_URL.'/pullfile.php?f='.$site1File.'&md5='.$site1FileMd5);

if ($site2Result == 'done') {
    unlink('./tmp/'.$site1File);
} else {
    echo '<p>
         Uploaded file failed to transfer to '.SITE_2_URL.'
          - but will be dealt with later.
         </p>';
}

这将是站点2上的“ pullfile.php”

// ----- Site 2, pullfile.php -----

// This script will pull a file from site 1 and
// place it in '/uploaded'

// used to cross-check the uploaded file
$fileMd5 = $_GET['md5'];
$fileName = basename($_GET['f']);

// we need to pull the file from the './tmp/' dir on site 1
$pulledFile = file_get_contents('http://'.SITE_1_URL.'/tmp/'.$fileName);

// save that file to disk
$result = file_put_contents('./uploaded/'.$fileName,$pulledFile);
if (! $result) {
    echo 'Error: problem writing file to disk';
    exit;
}

$pulledMd5 = md5_file('./uploaded/'.$fileName);
if ($pulledMd5 != $fileMd5) {
    echo 'Error: md5 mis-match';
    exit;
}

// At this point, everything should be right.
// We pass back 'done' to site 1, so we know 
// everything went smooth. This way, a 'blank'
// return can be treated as an error too.
echo 'done';
exit;