Django管理员 - 排序list_filter

Question

我在list_filter中有'version',我希望最新版本在'All'列表项之后.在这种情况下,如何对列表进行降序排序？(全部,3.6.99.108,3.6.99.107 ......)

Answer 1

在模型Meta类中定义默认排序:

class MyModel(models.Model):
    # some model fields here
    class Meta:
        ordering = ['-version',]

如果它不能满足您的目的,您可以编写自己的自定义列表过滤器:

from django.utils.translation import ugettext_lazy as _
from django.contrib.admin import SimpleListFilter

class VersionFilter(SimpleListFilter):
    title = _('version')

    parameter_name = 'version'

    def lookups(self, request, model_admin):
        qs = model_admin.queryset(request)
        return [(i, i) for i in qs.values_list('version', flat=True) \
                                  .distinct().order_by('-version')]

    def queryset(self, request, queryset):
        if self.value():
            return queryset.filter(version__exact=self.value())

class MyModel(ModelAdmin):
    list_filter = (VersionFilter,)

如果你得到以下错误,AttributeError: object has no attribute 'queryset'那么你可能正在使用Django 1.5+use,.get_queryset()例如

qs = model_admin.get_queryset(request)