如何序列化包含基本类型的元组和基本类型的数组？

Question

在 C# 4.0 中，我尝试Tuple<Guid, int[]>使用 DataContractSerializer 序列化和反序列化 a。我已经成功序列化和反序列化 type Guid、 typeint[]和 type Tuple<Guid, int>。如果我尝试序列化 type Tuple<Guid, int[]>，所有内容都会编译，但会出现以下运行时异常：

Type 'System.Int32[]' with data contract name 
'ArrayOfint:http://schemas.microsoft.com/2003/10/Serialization/Arrays'
is not expected. Consider using a DataContractResolver or add any types
not known statically to the list of known types - for example, by using
the KnownTypeAttribute attribute or by adding them to the list of known 
types passed to DataContractSerializer.

我的序列化和反序列化例程很简单：

public static string Serialize<T>(this T obj)
{
    var serializer = new DataContractSerializer(obj.GetType());
    using (var writer = new StringWriter())
    using (var stm = new XmlTextWriter(writer))
    {
        serializer.WriteObject(stm, obj);
        return writer.ToString();
    }
}

public static T Deserialize<T>(this string serialized)
{
    var serializer = new DataContractSerializer(typeof(T));
    using (var reader = new StringReader(serialized))
    using (var stm = new XmlTextReader(reader))
    {
        return (T)serializer.ReadObject(stm);
    }
}

为什么我会遇到此异常？我可以采取什么措施来解决或绕过它？在我看来，Tuple可以序列化的包含类型在序列化时应该没有问题。

Answer 1

像这样的事情怎么样？

class Program
{
    public static class DataContractSerializerFactory<T>
    {
        private static IEnumerable<Type> GetTypeArguments(Type t, IEnumerable<Type> values)
        {
            if (t.IsGenericType)
                foreach (var arg in t.GetGenericArguments())
                    values = values.Union(GetTypeArguments(arg, values));
            else
                values = values.Union(new[] { t });
            return values;
        }

        public static DataContractSerializer Create()
        {
            return new DataContractSerializer(typeof(T), GetTypeArguments(typeof(T), new[] { typeof(T) }));
        }
    }

    static void Main(string[] args)
    {
        var x = Tuple.Create(Guid.NewGuid(), new[] { 1, 2, 3, 4, 5, 6 });

        var serializer = DataContractSerializerFactory<Tuple<Guid, int[]>>.Create();

        var sb = new StringBuilder();
        using (var writer = XmlWriter.Create(sb))
        {
            serializer.WriteObject(writer, x);
            writer.Flush();
            Console.WriteLine(sb.ToString());
        }
    }
}

编辑：应该适用于任何嵌套泛型。仅考虑基本类型和叶类型参数。如果您希望中间容器也成为 KnownTypes 的一部分，应该很容易。