And*_*ers 5 cocoa-touch core-data objective-c nssortdescriptor ios
我有一个核心数据应用程序.我想要获取一种物体,User.User有财产userId.
我有另一个带有userIds的数组[1, 4, 3, 5].我想创建一个根据数组中s 的顺序对NSSortDescriptor我的User对象进行排序userId.
这可能吗,我应该怎么做?
更新
我现在尝试了以下内容.
我在我的User对象中添加了一个可转换属性,在那里我存储了用户id数组.
我尝试了以下排序描述符:
sortDescriptor = [[NSSortDescriptor alloc] initWithKey:@"userId" ascending:YES comparator:^NSComparisonResult(id obj1, id obj2) {
NSUInteger idx1 = [self.user.followingIds indexOfObject:[obj1 valueForKey:@"userId"]];
NSUInteger idx2 = [self.user.followingIds indexOfObject:[obj2 valueForKey:@"userId"]];
return idx1 - idx2;
}];
Run Code Online (Sandbox Code Playgroud)我收到以下错误:
Serious application error. Exception was caught during Core Data change processing. This is usually a bug within an observer of NSManagedObjectContextObjectsDidChangeNotification. [<__NSCFNumber 0xa337400> valueForUndefinedKey:]: this class is not key value coding-compliant for the key userId. with userInfo {
NSTargetObjectUserInfoKey = 2502;
NSUnknownUserInfoKey = userId;
}
*** Terminating app due to uncaught exception 'NSUnknownKeyException', reason: '[<__NSCFNumber 0xa337400> valueForUndefinedKey:]: this class is not key value coding- compliant for the key userId.'
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更新2
还想Followers在User对象之间添加关系.任何想法应该如何看待这种关系?见附图.那是对的吗?

使用排序描述符无法完成此操作,您必须在获取结果后应用自定义比较器函数:
NSArray *userIds = ...; // e.g. @[@1, @4, @3, @5]
NSArray *results = ...; // result of fetch request
NSArray *sorted = [results sortedArrayUsingComparator:^NSComparisonResult(id obj1, id obj2) {
NSUInteger idx1 = [userIds indexOfObject:[obj1 valueForKey:@"userId"]];
NSUInteger idx2 = [userIds indexOfObject:[obj2 valueForKey:@"userId"]];
return idx1 - idx2;
}];
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