symfony2使用另一个表单值验证表单值

Question

在Symfony2中,我使用自定义约束来验证表单上的某些数据,但我想知道是否可以从表单中引入一个值来验证其他值？

这是我的约束......

<?php
// src\BizTV\ContainerManagementBundle\Validator\Constraints\ContainerExists.php
namespace BizTV\ContainerManagementBundle\Validator\Constraints;

use Symfony\Component\Validator\Constraint;

/**
 * @Annotation
 */
class ContainerExists extends Constraint
{
    public $message = 'Namnet är upptaget, vänligen välj ett annat.';

    public function validatedBy()
    {
        return 'containerExists';
    }

}

我的验证员......

<?php 
// src\BizTV\ContainerManagementBundle\Validator\Constraints\ContainerExistsValidator.php
namespace BizTV\ContainerManagementBundle\Validator\Constraints;

use Symfony\Component\Validator\Constraint;
use Symfony\Component\Validator\ConstraintValidator;

use Symfony\Component\DependencyInjection\ContainerInterface as Container;
use Doctrine\ORM\EntityManager as EntityManager;

class ContainerExistsValidator extends ConstraintValidator
{

    private $container;
    private $em;

    public function __construct(Container $container, EntityManager $em) {
        $this->container = $container;
        $this->em = $em;
    }   

    public function isValid($value, Constraint $constraint)
    {

        $em = $this->em;
        $container = $this->container;

        $company = $this->container->get('security.context')->getToken()->getUser()->getCompany();

        //Fetch entities with same name
        $repository = $em->getRepository('BizTVContainerManagementBundle:Container');
        $query = $repository->createQueryBuilder('c')
            ->where('c.company = :company')
            ->setParameter('company', $company)
            ->orderBy('c.name', 'ASC')
            ->getQuery();
        $containers = $query->getResult();      

        foreach ($containers as $g) {
            if ($g->getName() == $value) {
                $this->setMessage('Namnet '.$value.' är upptaget, vänligen välj ett annat', array('%string%' => $value));
                return false;
            }
        }

        return true;
    }
}

通过服务使用......

services:
  biztv.validator.containerExists:
    class: BizTV\ContainerManagementBundle\Validator\Constraints\ContainerExistsValidator
    arguments: ['@service_container', '@doctrine.orm.entity_manager']      
    tags:
        - { name: validator.constraint_validator, alias: containerExists }

这是我如何将它像这样应用到我的实体......

<?php

namespace BizTV\ContainerManagementBundle\Entity;

use Doctrine\ORM\Mapping as ORM;
use Symfony\Component\Validator\Constraints as Assert;

use BizTV\ContainerManagementBundle\Validator\Constraints as BizTVAssert;

use BizTV\UserBundle\Entity\User as user;
use BizTV\ContainerManagementBundle\Entity\Container as Container;

/**
 * BizTV\ContainerManagementBundle\Entity\Container
 *
 * @ORM\Table(name="container")
 * @ORM\Entity
 */
class Container
{

    /**
     * @var integer $id
     * @ORM\Id
     * @ORM\Column(type="integer")
     * @ORM\GeneratedValue(strategy="AUTO")
     */
    protected $id;

    /**
     * @var string $name
     * @Assert\NotBlank(message = "Du måste ange ett namn") 
     * @BizTVAssert\ContainerExists
     * @ORM\Column(name="name", type="string", length=255, nullable=true)
     */
    private $name;

在我的验证器中,我希望能够完成这样的事情

public function isValid($FORM->OTHERVALUE, $value, Constraint $constraint)
{

    $em = $this->em;
    $container = $this->container;

    $company = $this->container->get('security.context')->getToken()->getUser()->getCompany();

    //Fetch entities with same name
    $repository = $em->getRepository('BizTVContainerManagementBundle:Container');
    $query = $repository->createQueryBuilder('c')
        ->where('c.company = :company')
        ->setParameter('company', $company)
        ->orderBy('c.name', 'ASC')
        ->getQuery();
    $containers = $query->getResult();      


        if ($g->getName() == $FORM->OTHERVALUE) {
            $this->setMessage('Namnet '.$value.' är upptaget, vänligen välj ett annat', array('%string%' => $value));
            return false;
        }


    return true;
}

Answer 1

您可以创建一个类约束验证器(http://symfony.com/doc/master/cookbook/validation/custom_constraint.html#class-constraint-validator),然后通过它可以获得对象本身.

首先,您需要创建一个Constraint类:

class ContainerExists extends Constraint
{
    public $message = 'Namnet är upptaget, vänligen välj ett annat.';

    public function validatedBy()
    {
        return 'containerExists';
    }

    public function getTargets()
{
    return self::CLASS_CONSTRAINT;
}
}

之后创建验证器本身,您可以访问该对象,而不仅仅是单个属性.

class ContainerExistsValidator extends ConstraintValidator {

    private $em;
    private $security_context;

    public function __construct(EntityManager $entityManager, $security_context) {
        $this->security_context = $security_context;
        $this->em = $entityManager;
    }

    public function validate($object, Constraint $constraint) {

        // do whatever you want with the object, and if something is wrong add a violation

                $this->context->addViolation($constraint->message, array('%string%' => 'something'));

            }

        }

    }

然后创建服务以访问实体管理器和东西:

validator.container_exists:
        class: YourBundleName\Validator\Constraints\ContainerExistsValidator
        arguments: ["@doctrine.orm.entity_manager", "@security.context"]
        tags:
            - { name: validator.constraint_validator, alias: containerExists }

在这种情况下,由于类约束验证器应用于类本身,而不是属性,因此需要将以下注释添加到类中.

use YourBundleName\Validator\Constraints as BackendAssert;

/**
 * @BackendAssert\ContainerExists
 */