如何将int列表转换为元组列表

Question

我想转换这样的列表

l1 = [1,2,3,4,5,6,7,8]

至

l2 = [(1,2),(3,4),(5,6),(7,8)]

因为想要循环

for x,y in l2:
    draw_thing(x,y)

Answer 1

一个好方法是:

from itertools import izip
it = iter([1, 2, 3, 4])
for x, y in izip(it, it):
    print x, y

输出:

1 2
3 4
>>> 

Answer 2

以尼克的回答为基础:

>>> from itertools import izip
>>> t = [1,2,3,4,5,6,7,8,9,10,11,12]
>>> for a, b in izip(*[iter(t)]*2):
...     print a, b
...
1 2
3 4
5 6
7 8
9 10
11 12
>>> for a, b, c in izip(*[iter(t)]*3):
...     print a, b, c
...
1 2 3
4 5 6
7 8 9
10 11 12
>>> for a, b, c, d in izip(*[iter(t)]*4):
...     print a, b, c, d
...
1 2 3 4
5 6 7 8
9 10 11 12
>>> for a, b, c, d, e, f in izip(*[iter(t)]*6):
...     print a, b, c, d, e, f
...
1 2 3 4 5 6
7 8 9 10 11 12
>>>

不太可读,但它显示了一种简洁的方式来获得你想要的任何大小元组.

Answer 3

使用python的切片操作符很简单:

l2 = zip(l1[0::2], l1[1::2])