将SQL地理转换为C#

Question

这个地理空间T-SQL代码的C#等价物是什么？

DECLARE @g geography;
DECLARE @h geography;
SET @g = geography::STGeomFromText('POLYGON((-122.358 47.653, -122.348 47.649, -122.348 47.658, -122.358 47.658, -122.358 47.653))', 4326);
SET @h = geography::Point(47.653, -122.358, 4326)

SELECT @g.STIntersects(@h)

我试图使用SqlGeometry数据类型在多边形中找到一个点- 并且可以使用上面的T-SQL; 但我不明白如何实现等效的C#代码.

Answer 1

试试这个:

public bool OneOffSTIntersect()
{
    var g =
        Microsoft.SqlServer.Types.SqlGeography.STGeomFromText(
            new System.Data.SqlTypes.SqlChars(
                "POLYGON((-122.358 47.653, -122.348 47.649, -122.348 47.658, -122.358 47.658, -122.358 47.653))"), 4326);
    // suffix "d" on literals below optional but explicit
    var h = Microsoft.SqlServer.Types.SqlGeography.Point(47.653d, -122.358d, 4326);

    // rough equivalent to SELECT
    System.Console.WriteLine(g.STIntersects(h));

    // Alternatively return from a C# method or property (get).
    return g.STIntersects(h);
}

MSDN的SqlGeography Methods页面链接到T-SQL中关键调用的每个C#等价物的信息 - 例如STIntersects.