new*_*ite 22 java user-interface swing unit-testing jtable
我想为GUI编写测试用例.我想知道你如何模拟JButton的点击,或者你如何提取JTable的元素.
出于此目的,我构建了一个简单的GUI,如果单击该按钮并且JTextfield为空,则将计数增加1,但如果提供了数字,则计数将替换为JTextfield中的整数.当然我想使用正则表达式来确保输入JTextfield的文本实际上是一个整数,但让我们假设用户不会乱七八糟并输入一个非整数.此外,JLabel在JTable添加新行时更新当前计数.
这是代码:
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import javax.swing.GroupLayout;
import javax.swing.JButton;
import javax.swing.JFrame;
import javax.swing.JLabel;
import javax.swing.JPanel;
import javax.swing.JScrollPane;
import javax.swing.JTable;
import javax.swing.JTextField;
import javax.swing.SwingUtilities;
import javax.swing.table.DefaultTableModel;
public class sampleGUI extends JFrame implements ActionListener {
private Integer previous_count;
private Integer current_count;
private JButton Button;
private JTable table;
private JTextField text;
private DefaultTableModel model;
private JScrollPane scroll;
private JLabel label;
public sampleGUI() {
previous_count = null;
current_count = 0;
JFrame frame = new JFrame("Sample");
JPanel panel = new JPanel();
GroupLayout layout = new GroupLayout(panel);
panel.setLayout(layout);
label = new JLabel("Current Count: " + Integer.toString(current_count));
text = new JTextField(15);
Button = new JButton("Change the Count!");
model = new DefaultTableModel();
model.addColumn("Previous Count");
model.addColumn("Current Count");
table = new JTable(model);
scroll = new JScrollPane(table);
layout.setHorizontalGroup(layout
.createParallelGroup(GroupLayout.Alignment.LEADING)
.addGroup(
layout.createSequentialGroup().addComponent(label)
.addComponent(text).addComponent(Button))
.addComponent(scroll));
layout.setVerticalGroup(layout
.createSequentialGroup()
.addGroup(
layout.createParallelGroup(
GroupLayout.Alignment.BASELINE)
.addComponent(label).addComponent(text)
.addComponent(Button)).addComponent(scroll));
Button.addActionListener(this);
frame.add(panel);
frame.pack();
frame.setVisible(true);
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
}
@Override
public void actionPerformed(ActionEvent e) {
if (e.getSource() == Button) {
if (text.getText().equals("")) {
previous_count = current_count;
current_count++;
label.setText("Current Count: "
+ Integer.toString(current_count));
model.addRow(new Object[] { current_count, previous_count });
} else {
previous_count = current_count;
current_count = Integer.parseInt(text.getText());
label.setText("Current Count: "
+ Integer.toString(current_count));
text.setText("");
model.addRow(new Object[] { current_count, previous_count });
}
table.changeSelection(table.getRowCount() - 1, 0, false,
false);
}
}
public static void main(final String[] args) {
SwingUtilities.invokeLater(new Runnable() {
public void run() {
sampleGUI gui = new sampleGUI();
}
});
}
}
Run Code Online (Sandbox Code Playgroud)
假设我想模拟打开GUI,然后单击按钮一次而不输入任何文本,然后输入1234并单击按钮,然后单击按钮而不输入任何文本,JTable应该有3列:{{1,0 },{1234,1},{1235,1234}}.我怎么能为此编写测试?谢谢!
S E*_*S E 18
Java SE附带了一个标准的工具,就是做这个,Robot类.我只是用它来为游戏编写机器人并通过套接字服务器/客户端对远程控制一台单独的计算机,但它实际上是为了自动化测试,所以它应该适合你.基本格式很简单:
Robot bot = new Robot();
bot.mouseMove(10,10);
bot.mousePress(InputEvent.BUTTON1_MASK);
//add time between press and release or the input event system may
//not think it is a click
try{Thread.sleep(250);}catch(InterruptedException e){}
bot.mouseRelease(InputEvent.BUTTON1_MASK);
Run Code Online (Sandbox Code Playgroud)
当然,您也可以使用适当的keyPress/keyRelease方法以类似的方式模拟键盘事件.我有时发现使用机器人类的screenCapture方法以及在屏幕上搜索图像并确定点击的位置是有用的.
注意:这不要求您正在测试的窗口是在awt/swing上构建的,但是它确实要求您使用的java实现支持awt.
| 归档时间: |
|
| 查看次数: |
31382 次 |
| 最近记录: |