如何在Windows 8中将字节数组转换为InMemoryRandomAccessStream或IRandomAccessStream

Question

现在我遇到的问题是如何在Windows 8中将字节数组转换为InMemoryRandomAccessStream或IRandomAccessStream？

这是我的代码,但它不起作用,请参考以下代码

internal static async Task<InMemoryRandomAccessStream> ConvertTo(byte[] arr)
{
    InMemoryRandomAccessStream randomAccessStream = new InMemoryRandomAccessStream();
    Stream stream = randomAccessStream.AsStream();
    await stream.WriteAsync(arr, 0, arr.Length);
    await stream.FlushAsync();

    return randomAccessStream;
}

然后我创建RandomAccessStreamReference并设置requst数据包以便将图像共享给其他应用程序

    private static async void OnDeferredImageStreamRequestedHandler(DataProviderRequest Request)
    {
        DataProviderDeferral deferral = Request.GetDeferral();
        InMemoryRandomAccessStream stream = await ConvertTo(arr);
        RandomAccessStreamReference referenceStream =
                    RandomAccessStreamReference.CreateFromStream(stream);
        Request.SetData(referenceStream);
    }

但结果是我无法将图像字节数组共享给其他应用程序,我的代码是否有问题？在我看来,将byte []转换为InMemoryRandomAccessStream时会发生错误,但它没有抛出异常.

有谁知道怎么做？如果你可以将字节数组转换为IRandomAccessStream,同样可以帮助我.或者我的代码中有其他错误？

Answer 1

在Windows 8.1上,我们添加AsRandomAccessStream扩展方法更加容易:

internal static IRandomAccessStream ConvertTo(byte[] arr)
{
    MemoryStream stream = new MemoryStream(arr);
    return stream.AsRandomAccessStream();
}

Answer 2

using在文档顶部添加语句.

using System.Runtime.InteropServices.WindowsRuntime;
internal static async Task<InMemoryRandomAccessStream> ConvertTo(byte[] arr)
{
    InMemoryRandomAccessStream randomAccessStream = new InMemoryRandomAccessStream();
    await randomAccessStream.WriteAsync(arr.AsBuffer());
    randomAccessStream.Seek(0); // Just to be sure.
                    // I don't think you need to flush here, but if it doesn't work, give it a try.
    return randomAccessStream;
}

Answer 3

一行：

internal static IRandomAccessStream ConvertTo(byte[] arr)
{
    return arr.AsBuffer().AsStream().AsRandomAccessStream();
}