blo*_*m17 0 sql database oracle
所以我有三张桌子.CUSTOMER(CustomerID,LastName,FirstName),PURCHASE(PurchaseID,ItemName)和TRANSACTION(CustomerID,PurchaseID,Date).
我遇到的问题是我需要获得专门购买"Paint"和"Books"两个项目的客户的全名,但是当我运行我的代码时,没有任何问题出现.这是我有的:
SELECT CUSTOMER.FirstName, CUSTOMER.LastName
FROM CUSTOMER, PURCHASE
WHERE PURCHASE.Item = 'Paint' AND PURCHASE.Item = 'Books'
GROUP BY CUSTOMER.LastName, CUSTOMER.FirstName;
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请帮助,我真的很新,我真的很想得到一些帮助.
这种类型的问题被称为Relational Division.
SELECT CUSTOMER.FirstName, CUSTOMER.LastName
FROM CUSTOMER
INNER JOIN TRANSACTION
ON CUSTOMER.CustomerID = TRANSACTION.CustomerID
INNER JOIN PURCHASE
ON TRANSACTION.PurchaseID = PURCHASE.PurchaseID
WHERE PURCHASE.Item IN ('Paint', 'Books') -- list all items here
GROUP BY CUSTOMER.LastName, CUSTOMER.FirstName
HAVING COUNT(DISTINCT PURCHASE.Item) = 2 -- the total number of items searched
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如果每个事务UNIQUE都有ItemName一个强制执行的约束,则可以使用*
SELECT CUSTOMER.FirstName, CUSTOMER.LastName
FROM CUSTOMER
INNER JOIN TRANSACTION
ON CUSTOMER.CustomerID = TRANSACTION.CustomerID
INNER JOIN PURCHASE
ON TRANSACTION.PurchaseID = PURCHASE.PurchaseID
WHERE PURCHASE.Item IN ('Paint', 'Books')
GROUP BY CUSTOMER.LastName, CUSTOMER.FirstName
HAVING COUNT(*) = 2
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