我是angularjs开发的新手,我写了这个简单的应用程序,但是在启动时从ajax请求加载模型后,我不知道如何更新视图!
当我在photos.php中添加延迟时,此代码不起作用,使用:sleep(3); 用于模拟远程服务器延迟!相反,如果search.php是快速的,它的工作!
<!doctype html>
<html ng-app="photoApp">
<head>
<title>Photo Gallery</title>
</head>
<body>
<div ng-view></div>
<script src="../angular.min.js"></script>
<script>
'use strict';
var photos = []; //model
var photoAppModule = angular.module('photoApp', []);
photoAppModule.config(function($routeProvider) {
$routeProvider.when('/photos', {
templateUrl: 'photo-list.html',
controller: 'listCtrl' });
$routeProvider.otherwise({redirectTo: '/photos'});
})
.run(function($http) {
$http.get('photos.php')//load model with delay
.success(function(json) {
photos = json; ///THE PROBLEM HERE!! if photos.php is slow DON'T update the view!
});
})
.controller('listCtrl', function($scope) {
$scope.photos = photos;
});
</script>
</body>
</html>
输出photos.php
[{"file": "cat.jpg", "description": "my cat in my house"},
{"file": "house.jpg", "description": "my house"},
{"file": "sky.jpg", "description": "sky over my house"}]
照片list.html
<ul>
<li ng-repeat="photo in photos ">
<a href="#/photos/{{ $index }}">
<img ng-src="images/thumb/{{photo.file}}" alt="{{photo.description}}" />
</a>
</li>
</ul>
编辑1,推迟解决方案:
.run(function($http, $q) {
var deferred = $q.defer();
$http.get('photos.php')//load model with delay
.success(function(json) {
console.log(json);
photos = json; ///THE PROBLEM!! if photos.php is slow DON'T update the view!
deferred.resolve(json);//THE SOLUTION!
});
photos = deferred.promise;
})
编辑2,服务解决方案:
...
//require angular-resource.min.js
angular.module('photoApp.service', ['ngResource']).factory('photoList', function($resource) {
var Res = $resource('photos.php', {},
{
query: {method:'GET', params:{}, isArray:true}
});
return Res;
});
var photoAppModule = angular.module('photoApp', ['photoApp.service']);
...
.run(function($http, photoList) {
photos = photoList.query();
})
...
简短的回答是这样的:
.controller('listCtrl', ['$scope', '$timeout', function($scope, $timeout) {
$timeout(function () {
$scope.photos = photos;
}, 0);
}]);
答案很长:请不要像这样混合常规的javascript和角度.重新编写代码,以便angular知道任何时候发生了什么.
var photoAppModule = angular.module('photoApp', []);
photoAppModule.config(function($routeProvider) {
$routeProvider.when('/photos', {
templateUrl: 'photo-list.html',
controller: 'listCtrl'
});
$routeProvider.otherwise({redirectTo: '/photos'});
});
photoAppModule.controller('listCtrl', ['$scope', function($scope) {
$scope.photos = {};
$http.get('photos.php') // load model with delay
.success(function(json) {
$scope.photos = json; // No more problems
});
}]);
您需要将视图中的元素绑定到$scope对象的属性（简单或对象）。一旦 $scope 对象更新，视图应该自行更新。这就是 AngularJS 的美妙之处。
编辑：请将您的控制器注册为
photoAppModule.controller('listCtrl', function($scope){
$scope.photos = photos;
});
如果 photos 变量不可用，那么您可能必须使用该变量创建一个服务并注入控制器。