ama*_*nda 20 c c++ math trigonometry
假设左上角是(0,0)并且我给出了30度的角度,起点为(0,300),线长度为600,我该如何计算线的终点以便该线代表给定的角度.
C伪代码是
main() {
int x,y;
getEndPoint(30, 600, 0, 300, &x, &y);
printf("end x=%d, end y=%d", x, y);
}
// input angle can be from 0 - 90 degrees
void getEndPoint(int angle, int len, int start_x, int start_y, int *end_x, int *end_y)
{
calculate the endpoint here for angle and length
*end_x = calculated_end_x;
*end_y = calculated_end_y;
}
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Nic*_*unt 39
// edit to add conversion
#define radian2degree(a) (a * 57.295779513082)
#define degree2radian(a) (a * 0.017453292519)
x = start_x + len * cos(angle);
y = start_y + len * sin(angle);
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