随机整数/出现(C++)问题

Question

我目前一直困在一个C++问题大约一个半小时.这是问题:

编写一个程序,生成0到9之间的100个随机整数,并显示每个数字的计数.(提示:使用rand()%10生成0到9之间的随机整数.使用十个整数的数组,比如计数,来存储O,l,...,9的数量的计数.)

这就是我到目前为止所拥有的.我认为我非常接近,但我对每个随机整数的出现次数(或计数)保持"0".任何帮助将不胜感激.

const int SIZE = 100;

int main()
{
int integers[SIZE];
int index;
int zero = 0;
int one = 0;
int two = 0;
int three = 0;
int four = 0;
int five = 0;
int six = 0;
int seven = 0;
int eight = 0;
int nine = 0;

cout << "The following 100 integers are random:" << endl;
cout << endl;

srand(time(0));

for (index = 0; index < SIZE; index++)
{
    integers[SIZE] = rand() % 10;
    cout << integers[SIZE] << " ";
}

cout << endl;

for (index = 0; index < SIZE; index++)
{
    if (integers[index] == 0)
    {
        zero += 1;
    }
}

for (index = 0; index < SIZE; index++)
{
    if (integers[index] == 1)
    {
        one += 1;
    }
}

for (index = 0; index < SIZE; index++)
{
    if (integers[index] == 2)
    {
        two += 1;
    }
}

for (index = 0; index < SIZE; index++)
{
    if (integers[index] == 3)
    {
        three += 1;
    }
}

for (index = 0; index < SIZE; index++)
{
    if (integers[index] == 4)
    {
        four += 1;
    }
}

for (index = 0; index < SIZE; index++)
{
    if (integers[index] == 5)
    {
        five += 1;
    }
}

for (index = 0; index < SIZE; index++)
{
    if (integers[index] == 6)
    {
        six += 1;
    }
}

for (index = 0; index < SIZE; index++)
{
    if (integers[index] == 7)
    {
        seven += 1;
    }
}

for (index = 0; index < SIZE; index++)
{
    if (integers[index] == 8)
    {
        eight += 1;
    }
}

for (index = 0; index < SIZE; index++)
{
    if (integers[index] == 9)
    {
        nine += 1;
    }
}

cout << "The number of zeros in the random list are " << zero << endl;
cout << "The number of ones in the random list are " << one << endl;
cout << "The number of twos in the random list are " << two << endl;
cout << "The number of threes in the random list are " << three << endl;
cout << "The number of fours in the random list are " << four << endl;
cout << "The number of fives in the random list are " << five << endl;
cout << "The number of sixes in the random list are " << six << endl;
cout << "The number of sevens in the random list are " << seven << endl;
cout << "The number of eights in the random list are " << eight << endl;
cout << "The number of nines in the random list are " << nine << endl;

getch();

return 0;

}

Answer 1

您有未定义的行为,因为您将其SIZE用作数组的索引而不是index:

for (index = 0; index < SIZE; index++)
{
    integers[SIZE] = rand() % 10;
    cout << integers[SIZE] << " ";
}

这将访问数组的边界之外(因为范围是从)0到SIZE-1.在循环体内,SIZE改为index.

但是,我认为它会帮助您重新阅读您的问题陈述.特别:

例如,使用十个整数的数组counts来存储0s,1s,...,9s的计数

而是使用数组来存储随机数.这根本不是必需的.您无需跟踪生成的数字.您只需要在适当的计数中加1,然后您就可以简单地丢弃随机数.

你应该简单地用所谓的阵列counts,其中counts[0]门店数量0这么远,counts[1]门店数量1,S等等,那么你不需要这些可怕的变量叫zero,one,two,等等.如果您发现自己定义了类似的变量名称(其中数字越来越多),那么您应该使用数组代替.