按州和名义获取工作？

Question

Powershell v3.

Start-Job -Name "TestJob" -ScriptBlock { Write-Host "foo" }

工作开始很好.然后我输入

Get-Job

我明白了

Id   Name      PSJobTypeName   State      HasMoreData   Location      Command
--   ----      -------------   -----      -----------   --------      -------
18   TestJob   BackgroundJob   Completed  True          localhost     Write-Host "foo"

到目前为止,一切都按计划进行.但现在让我们说我在这个会话中有很多工作,他们有各种不同的名字.所以我想只找到名为TestJob的作业:

Get-Job -Name TestJob

这也完全按预期工作,只返回该名称的作业.但现在让我们说我想要找到名为TestJob 且仍在运行的作业:

PS C:\> Get-Job -Name TestJob -State Running
Get-Job : Parameter set cannot be resolved using the specified named parameters.
At line:1 char:1
+ Get-Job -Name TestJob -State Running
+ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
    + CategoryInfo          : InvalidArgument: (:) [Get-Job], ParameterBindingException
    + FullyQualifiedErrorId : AmbiguousParameterSet,Microsoft.PowerShell.Commands.GetJobCommand

有没有办法做到这一点？

Answer 1

请尝试以下方法

Get-Job -State Completed | Where-Object {$_.Name.Contains("TestJob")}

这是基于您的示例的示例运行

PS D:\>  Get-Job -State Completed | Where-Object {$_.Name.Contains("Job")}

Id              Name            State      HasMoreData     Location             Command
--              ----            -----      -----------     --------             -------
1               TestJob         Completed  True            localhost             Write-Host "foo"
3               TestJob         Completed  True            localhost             Write-Host "foo"

有关Get-Help Where-Object详细信息,请参阅.