C++中有新的返回(void*)吗？

Question

这是一个简单的问题:

使用new运算符是否返回类型指针(void*)？请参阅new/delete和malloc/free之间的区别是什么？答案 - 它说new returns a fully typed pointer while malloc void *

但根据http://www.cplusplus.com/reference/new/operator%20new/

throwing (1)    
void* operator new (std::size_t size) throw (std::bad_alloc);
nothrow (2) 
void* operator new (std::size_t size, const std::nothrow_t& nothrow_value) throw();
placement (3)   
void* operator new (std::size_t size, void* ptr) throw();

这意味着它返回一个类型为(void*)的指针,如果它返回(void*)我从未见过像MyClass*ptr =(MyClass*)new MyClass这样的代码;

我很困惑.

编辑

根据http://www.cplusplus.com/reference/new/operator%20new/ example

std::cout << "1: ";
  MyClass * p1 = new MyClass;
      // allocates memory by calling: operator new (sizeof(MyClass))
      // and then constructs an object at the newly allocated space

  std::cout << "2: ";
  MyClass * p2 = new (std::nothrow) MyClass;
      // allocates memory by calling: operator new (sizeof(MyClass),std::nothrow)
      // and then constructs an object at the newly allocated space

所以MyClass * p1 = new MyClass调用operator new (sizeof(MyClass)),因为如果我正确理解语法,它应该返回.throwing (1)
void* operator new (std::size_t size) throw (std::bad_alloc);(void *)

谢谢

Answer 1

你很困惑operator new(确实返回void*)和new操作符(返回一个完全类型的指针).

void* vptr = operator new(10); // allocates 10 bytes
int* iptr = new int(10); // allocate 1 int, and initializes it to 10