将双精度列表格式化为字符串

use*_*326 2 printf haskell map

我正在尝试将双打列表格式化为字符串.我想把一个列表如下:

[0.38, 0.94]
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变成这样的东西:

"aString 0.380  0.940"
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我试过了:

"aString" ++ map (printf "%7.3f") [0.38, 0.94]
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并得到反馈:

<interactive>:80:19:
    No instance for (PrintfType Char)
      arising from a use of `printf'
    Possible fix: add an instance declaration for (PrintfType Char)
    In the first argument of `map', namely `(printf "%7.3f")'
    In the second argument of `(++)', namely
      `map (printf "%7.3f") [0.38, 0.94]'
    In the expression: "aString" ++ map (printf "%7.3f") [0.38, 0.94]
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我无法解决这个问题.我无法撰写有效的签名.

谢谢

Fre*_*Foo 12

问题是map (printf "%7.3f") [0.38, 0.94]类型[String],而不是String.用途concatMap:

Prelude Text.Printf> "aString" ++ concatMap (printf "%7.3f") [0.38, 0.94]
"aString  0.380  0.940"
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