用Python打开文件

Question

当我尝试在我的python程序中打开文件时,即使它们位于同一目录中,我也会收到一个奇怪的错误.这是我的代码:

def main():
#filename = input("Enter the name of the file of grades: ")

file = open("g.py", "r")
for line in file:
    points = 0

    array = line.split()

    if array[1] == 'A':
        points = array[2] * 4
    elif array[1] == 'B':
        points = array[2] * 3
    elif array[1] == 'C':
        points = array[2] * 2
    elif array[1] == 'D':
        points = array[2] * 1

    totalpoints += points
    totalpointspossible += array[2]*4

gpa = (totalpoints/totalpointspossible)*4
print("The GPA is ", gpa)

file.close()

main()

这是我得到的错误:

Traceback (most recent call last):
File "yotam2.py", line 51, in <module>
main()
File "yotam2.py", line 28, in main
file = open(g.py, "r")
NameError: global name 'g' is not defined

我不太确定为什么它没有定义g,即使它与我的python文件在同一目录中.

Answer 1

g.py 应该是一个字符串:

file = open("g.py", "r")

此外,array是一个字符串列表.用整数乘以字符串只是复制它们:

>>> "1" * 4
"1111"

你必须转换array(顺便说一下,这不是一个数组)到一个数字列表:

array = [int(n) for n in line.split()]