Cai*_*ifa 24 ruby string function
我可以用Ruby测量两个字符串之间的距离吗?
即:
compare('Test', 'est') # Returns 1
compare('Test', 'Tes') # Returns 1
compare('Test', 'Tast') # Returns 1
compare('Test', 'Taste') # Returns 2
compare('Test', 'tazT') # Returns 5
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Mic*_*nzl 25
由于本机C绑定,更容易和更快:
gem install levenshtein-ffi
gem install levenshtein
require 'levenshtein'
Levenshtein.normalized_distance string1, string2, threshold
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http://rubygems.org/gems/levenshtein http://rubydoc.info/gems/levenshtein/0.2.2/frames
Hug*_*lio 24
我找到了这个给你:
def levenshtein_distance(s, t)
m = s.length
n = t.length
return m if n == 0
return n if m == 0
d = Array.new(m+1) {Array.new(n+1)}
(0..m).each {|i| d[i][0] = i}
(0..n).each {|j| d[0][j] = j}
(1..n).each do |j|
(1..m).each do |i|
d[i][j] = if s[i-1] == t[j-1] # adjust index into string
d[i-1][j-1] # no operation required
else
[ d[i-1][j]+1, # deletion
d[i][j-1]+1, # insertion
d[i-1][j-1]+1, # substitution
].min
end
end
end
d[m][n]
end
[ ['fire','water'], ['amazing','horse'], ["bamerindos", "giromba"] ].each do |s,t|
puts "levenshtein_distance('#{s}', '#{t}') = #{levenshtein_distance(s, t)}"
end
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这是非常棒的输出:=)
levenshtein_distance('fire', 'water') = 4
levenshtein_distance('amazing', 'horse') = 7
levenshtein_distance('bamerindos', 'giromba') = 9
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资料来源:http://rosettacode.org/wiki/Levenshtein_distance#Ruby
Nak*_*lon 15
在Rubygems中有一个实用方法实际上应该是公共的但不是,不管怎么说:
require "rubygems/text"
ld = Class.new.extend(Gem::Text).method(:levenshtein_distance)
p ld.call("asd", "sdf") => 2
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Dig*_*oss 14
更简单的是,我有时会露出红宝石......
# Levenshtein distance, translated from wikipedia pseudocode by ross
def lev s, t
return t.size if s.empty?
return s.size if t.empty?
return [ (lev s.chop, t) + 1,
(lev s, t.chop) + 1,
(lev s.chop, t.chop) + (s[-1, 1] == t[-1, 1] ? 0 : 1)
].min
end
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Ruby 2.3 及更高版本附带did_you_meangem,其中包括DidYouMean::Levenshtein.distance. 适用于大多数情况,默认可用。
DidYouMean::Levenshtein.distance("Test", "est") # => 1
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我制作了一个damerau-levenshtein gem,其中算法是用 C 实现的
require "damerau-levenshtein"
dl = DamerauLevenshtein
dl.distance("Something", "Smoething") #returns 1
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