我有一个脚本正在创建一个表,然后插入一行.这是我执行创建表的SQL代码:
CREATE TABLE polls (
id INT NOT NULL UNIQUE AUTO_INCREMENT,
name VARCHAR(255) NOT NULL UNIQUE,
author VARCHAR(255) NOT NULL,
created DATETIME NOT NULL,
expires DATETIME,
PRIMARY KEY(id)
)
Run Code Online (Sandbox Code Playgroud)
这是我添加新行的地方:
INSERT INTO polls
VALUES ('TestPoll'),('Billy Bob'),('2013-05-01 04:17:31'),('2013-05-01 04:17:31')
Run Code Online (Sandbox Code Playgroud)
要么
INSERT INTO polls
VALUES ('TestPoll','Billy Bob','2013-05-01 04:17:31','2013-05-01 04:17:31')
Run Code Online (Sandbox Code Playgroud)
(无论如何我得到同样的错误)
我总是得到这个错误:
<class '_mysql_exceptions.OperationalError'>, OperationalError(1136, "Column count doesn't match value count at row 1"), <traceback object at 0x7f7bed982560>
Run Code Online (Sandbox Code Playgroud)
你的语法错了,试试:
INSERT INTO polls
VALUES ('TestPoll','Billy Bob','2013-05-01 04:17:31','2013-05-01 04:17:31')
Run Code Online (Sandbox Code Playgroud)
但如果您的表结构发生变化,您的代码将会中断,更安全的版本是:
INSERT INTO polls (name, author, created, expires)
VALUES ('TestPoll','Billy Bob','2013-05-01 04:17:31','2013-05-01 04:17:31')
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
3855 次 |
| 最近记录: |