Cor*_*oyd 6 cocoa cocoa-touch objective-c
有没有办法获得像类的所有键值对的字典?
你必须使用Objective-C Runtime函数自己动手.这是一些非常基本的示例代码.请注意,获取类的ivars不会获得其超类的ivars.您需要明确地执行此操作,但函数都在运行时中.
#import <objc/objc-runtime.h>
#include <inttypes.h>
#include <Foundation/Foundation.h>
@interface Foo : NSObject
{
int i1;
}
@end
@implementation Foo
@end
@interface Bar : Foo
{
NSString* s1;
}
@end
@implementation Bar
@end
int main(int argc, char** argv)
{
NSAutoreleasePool* pool = [[NSAutoreleasePool alloc] init];
unsigned int count;
Ivar* ivars = class_copyIvarList([Bar class], &count);
for(unsigned int i = 0; i < count; ++i)
{
NSLog(@"%@::%s", [Bar class], ivar_getName(ivars[i]));
}
free(ivars);
[pool release];
}
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我不确定只有ivars但是如果你将它们定义为属性,则可以访问类的可用属性.
我一直在为几个项目使用SQLitePersistentObjects,它有一些有用的代码,可以获取在类中定义的属性,以便在与sqlite进行序列化时使用.
它使用函数class_copyPropertyList来获取类的可用属性列表.
进一步来说:
+(NSDictionary *)propertiesWithEncodedTypes
{
// DO NOT use a static variable to cache this, it will cause problem with subclasses of classes that are subclasses of SQLitePersistentObject
// Recurse up the classes, but stop at NSObject. Each class only reports its own properties, not those inherited from its superclass
NSMutableDictionary *theProps;
if ([self superclass] != [NSObject class])
theProps = (NSMutableDictionary *)[[self superclass] propertiesWithEncodedTypes];
else
theProps = [NSMutableDictionary dictionary];
unsigned int outCount;
objc_property_t *propList = class_copyPropertyList([self class], &outCount);
int i;
// Loop through properties and add declarations for the create
for (i=0; i < outCount; i++)
{
objc_property_t * oneProp = propList + i;
NSString *propName = [NSString stringWithUTF8String:property_getName(*oneProp)];
NSString *attrs = [NSString stringWithUTF8String: property_getAttributes(*oneProp)];
NSArray *attrParts = [attrs componentsSeparatedByString:@","];
if (attrParts != nil)
{
if ([attrParts count] > 0)
{
NSString *propType = [[attrParts objectAtIndex:0] substringFromIndex:1];
[theProps setObject:propType forKey:propName];
}
}
}
free(propList);
return theProps;
}
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这将返回属性的字典 - 您需要对您获得的结果进行一些调查,但如果您使用属性,则应该能够获得所需的内容.