如何使用Jersey客户端POST方法提交数据

Question

我是泽西岛的新手.我需要实现Jersey客户端以POST方法提交数据.curl命令是:

curl -d '{"switch": "00:00:00:00:00:00:00:01", "name":"flow-mod-1", "priority":"32768", "ingress-port":"1","active":"true", "actions":"output=2"}' http://localhost:8080/wm/staticflowentrypusher/json

所以我想弄清楚如何使用Jersey客户端来实现上面的curl命令.

到目前为止我做了:

public class FLClient {

private static Client client;
private static WebResource webResource;
private static String baseuri = "http://localhost:8080/wm/staticflowentrypusher/json";
private static ClientResponse response;
private static String output = null;

public static void main(String[] args) {
    try {

        client = Client.create();

        webResource = client.resource(baseuri);

                    // implement POST data 

    } catch (Exception e) {
        e.printStackTrace();
    }
}

}

有人可以帮我吗？

Answer 1

现在我明白了.这是我的解决方案:

public static void main(String[] args) {

    try {
        Client client = Client.create();

        WebResource webResource = client.resource(baseuri);

        String input = "{\"switch\": \"00:00:00:00:00:00:00:01\", "
                + "\"name\":\"flow-mod-1\", \"priority\":\"32768\", "
                + "\"ingress-port\":\"1\",\"active\":\"true\", "
                + "\"actions\":\"output=2\"}";

        // POST method
        ClientResponse response = webResource.accept("application/json")
                .type("application/json").post(ClientResponse.class, input);

        // check response status code
        if (response.getStatus() != 200) {
            throw new RuntimeException("Failed : HTTP error code : "
                    + response.getStatus());
        }

        // display response
        String output = response.getEntity(String.class);
        System.out.println("Output from Server .... ");
        System.out.println(output + "\n");
    } catch (Exception e) {
        e.printStackTrace();
    }

}

Answer 2

如果你想在JSON体内发帖,这是一个更好的方法.

ClientConfig clientConfig = new DefaultClientConfig();              
clientConfig.getFeatures().put(JSONConfiguration.FEATURE_POJO_MAPPING, Boolean.TRUE);     
client = Client.create(clientConfig);

WebResource webResource = client.resource(baseuri);

Map<String,Object> postBody = new HashMap<String,Object>();
//put switch, name,priority....
ClientResponse response = webResource.accept("application/json")
                .type("application/json").post(ClientResponse.class, postBody);

记住你必须包括 jersey-json

Answer 3

对于未来的用户来说,随着新版本的jersey东西发生了变化,所以做这种POST方法的方法是:

• 对于版本1.x(@Li' 回答):

  WebResource webResource = client.resource(baseuri);
  
  String input = "...";
  
  ClientResponse response = webResource.accept("application/json")
          .type("application/json").post(ClientResponse.class, input);
  

• 对于版本2.x:

  WebTarget webTarget = client.target(baseuri);
  
  String input = "...";
  
  Response response = webTarget.request("application/json").post(Entity.json(input));
  

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