如何在shell中获取pythonpath？

Question

debian@debian:~$ echo $PYTHONPATH  
/home/qiime/lib/:  
debian@debian:~$ python  
Python 2.7.3 (default, Jan  2 2013, 16:53:07)   
[GCC 4.7.2] on linux2  
Type "help", "copyright", "credits" or "license" for more information.  
>>> import sys  
>>> sys.path  
['', '/usr/local/lib/python2.7/dist-packages/feedparser-5.1.3-py2.7.egg',   
'/usr/local/lib/python2.7/dist-packages/stripogram-1.5-py2.7.egg', '/home/qiime/lib', 
'/home/debian', '/usr/lib/python2.7', '/usr/lib/python2.7/plat-linux2',   
'/usr/lib/python2.7/lib-tk', '/usr/lib/python2.7/lib-old', '/usr/lib/python2.7/lib-
dynload',   '/usr/local/lib/python2.7/dist-packages', '/usr/lib/python2.7/dist-packages', 
'/usr/lib/python2.7/dist-packages/PIL', '/usr/lib/python2.7/dist-packages/gst-0.10',  
'/usr/lib/python2.7/dist-packages/gtk-2.0', '/usr/lib/pymodules/python2.7']    

如何在bash中获得所有pythonpath输出？
为什么 PYTHONPATH不能得到所有这些？

Answer 1

环境变量PYTHONPATH实际上只被添加到Python搜索模块的位置列表中.您可以在终端中打印完整列表,如下所示:

python -c "import sys; print(sys.path)"

或者如果想要UNIX目录列表样式(由分隔符:)输出,您可以这样做:

python -c "import sys; print(':'.join(x for x in sys.path if x))"

这将输出如下内容:

/usr/local/lib/python2.7/dist-packages/feedparser-5.1.3-py2.7.egg:/usr/local/lib/
python2.7/dist-packages/stripogram-1.5-py2.7.egg:/home/qiime/lib:/home/debian:/us
r/lib/python2.7:/usr/lib/python2.7/plat-linux2:/usr/lib/python2.7/lib-tk:/usr/lib
/python2.7/lib-old:/usr/lib/python2.7/lib- dynload:/usr/local/lib/python2.7/dist-
packages:/usr/lib/python2.7/dist-packages:/usr/lib/python2.7/dist-packages/PIL:/u
sr/lib/python2.7/dist-packages/gst-0.10:/usr/lib/python2.7/dist-packages/gtk-2.0:
/usr/lib/pymodules/python2.7

Answer 2

写吧:

只需在你的终端中编写哪个python,你就会看到你正在使用的python路径.

Answer 3

您也可以尝试以下操作：

Python 2.x：
python -c "import sys; print '\n'.join(sys.path)"

Python 3.x：
python3 -c "import sys; print('\n'.join(sys.path))"

输出将更加可读和干净，如下所示：

/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python27.zip /System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7 /System/Library/Frameworks/Python.framework /Versions/2.7/lib/python2.7/plat-darwin /System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/plat-mac /System/Library/Frameworks/Python.framework/Versions /2.7/lib/python2.7/plat-mac/lib-scriptpackages /System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/lib-tk /System/Library/Frameworks/Python.framework /Versions/2.7/lib/python2.7/lib-old /System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/lib-dynload /Library/Python/2.7/site-packages /System /Library/Frameworks/Python.framework/Versions/2.7/Extras/lib/python /System/Library/Frameworks/Python.framework/Versions/2.7/Extras/lib/python/PyObjC

Answer 4

Python 在启动时将一堆值加载到sys.path（通过字符串列表“实现”），包括：

• 各种硬编码的地方
• 的价值 $PYTHONPATH
• 可能是启动文件中的一些东西（我不确定 Python 是否有rcfiles）

$PYTHONPATH只是 的最终值的一部分sys.path。

如果您追求 的值sys.path，最好的方法是询问 Python（感谢 @Codemonkey）：

python -c "import sys; print sys.path"

Answer 5

我们这些使用Python 3.x的人应该这样做:

python -c "import sys; print(sys.path)"