当我将随机数添加到单独线程上的列表框时,UI会冻结

Question

当我加载窗体时,使用新线程,我每秒向列表框添加一个随机数,当它达到10个数字时,我生成一组10个随机数.但是,目前,我遇到了UI线程的问题.随机数被添加到列表框中,但我无法控制表单.当我尝试与表单进行交互时,UI会冻结.我是否错误地使用了MethodInvoker.任何意见,将不胜感激.

public Form1()
    {
        InitializeComponent();
        Thread ranThread = new Thread(new ThreadStart(RandomList));
        ranThread.IsBackground = true;
        ranThread.Start();         
    }

public void RandomList()
    {
        stack = new Stack<int>(); 
        while (loop)
        {
            if (lbxStackRndNum.InvokeRequired)
            {
                lbxStackRndNum.Invoke(new MethodInvoker(delegate
                    {
                        Random rnd = new Random();

                        if (lbxStackRndNum.Items.Count == 10)
                        {
                            stack.Clear();
                            lbxStackRndNum.Items.Clear();
                        }

                        int rndVal = rnd.Next(1, 10000);
                        stack.Push(rndVal);
                        lbxStackRndNum.Items.Insert(0, rndVal);
                        Thread.Sleep(1000);
                    }));
            }
        }
    }

Answer 1

你Thread.Sleep(1000)在调用的委托中调用,这意味着它将使UI线程休眠而不是ranThread.

public void RandomList()
{
    stack = new Stack<int>(); 
    while (loop)
    {
        if (lbxStackRndNum.InvokeRequired)
        {
            lbxStackRndNum.Invoke(new MethodInvoker(delegate
                {
                    Random rnd = new Random();

                    if (lbxStackRndNum.Items.Count == 10)
                    {
                        stack.Clear();
                        lbxStackRndNum.Items.Clear();
                    }

                    int rndVal = rnd.Next(1, 10000);
                    stack.Push(rndVal);
                    lbxStackRndNum.Items.Insert(0, rndVal);
                }));
              Thread.Sleep(1000);
        }
    }
}