INSERT存储过程(PL/SQL)

Dmi*_*try 0 oracle stored-procedures insert

我是PL/SQL和存储过程的新手.我正在尝试编写一个将通过CallableStatement从Java程序执行的存储过程.该过程采用两个参数,获取最后一条记录的id,递增它并使用新增加的id插入新记录.我在网上发现了一些主要做同样事情的例子,但我无法解决错误.

CREATE OR REPLACE PROCEDURE insertEmployeeProcedure
(lastname IN VARCHAR, firstname IN VARCHAR) AS
BEGIN
    lastEmpId NUMBER := SELECT COUNT(*) 
    INTO lastEmpId 
    FROM Employees;

    INSERT INTO Employees(id, lname, fname) VALUES(lastEmpId + 1, lastname, firstname);
END insertEmployeeProcedure;
/
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错误是:

Executed successfully in 0.018 s, 0 rows affected.
Line 1, column 1
Error code 984, SQL state 42000: ORA-00984: column not allowed here
Line 8, column 5
Error code 900, SQL state 42000: ORA-00900: invalid SQL statement
Line 9, column 1
Error code 0, SQL state null: java.lang.NullPointerException
Line 9, column 1
Execution finished after 0.018 s, 3 error(s) occurred.
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据我所知,存储过程是PL和SQL的混合.说,我尝试递增lastEmpId(如lastEmpId:= lastEmpId + 1),但得到了"无效的SQL语句"错误.此外,Oracle docs(http://docs.oracle.com/cd/B28359_01/appdev.111/b28843/tdddg_procedures.htm#CIHBCBHC)在解释如何在存储过程中定义和使用局部变量方面做得不好.

提前致谢.

Ale*_*man 5

你可能想要这样的东西

CREATE OR REPLACE PROCEDURE insertEmployeeProcedure
(lastname IN VARCHAR, firstname IN VARCHAR) AS 

   lastEmpId NUMBER;
 BEGIN
    SELECT COUNT(*) 
    INTO lastEmpId 
    FROM Employees;

    INSERT INTO Employees(id, lname, fname) VALUES(lastEmpId + 1, lastname, firstname); 
 END insertEmployeeProcedure; 
 /
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请注意,变量在BEGIN部分之前声明.

另外,如果您使用SQL开发人员,则在执行包创建代码后运行

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在您实际调用该过程之前,它会向您显示任何问题.