use*_*287 11 python regex beautifulsoup
如何找到'blue'包含以下格式的文本类的所有span :
04/18/13 7:29pm
因此可能是:
04/18/13 7:29pm
要么:
Posted on 04/18/13 7:29pm
在构建执行此操作的逻辑方面,这是我到目前为止所得到的:
new_content = original_content.find_all('span', {'class' : 'blue'}) # using beautiful soup's find_all
pattern = re.compile('<span class=\"blue\">[data in the format 04/18/13 7:29pm]</span>') # using re
for _ in new_content:
result = re.findall(pattern, _)
print result
我一直指的是/sf/answers/541297921/和/sf/answers/856039411/试图找到一种方法来做到这一点,但以上就是我到目前为止所有的.
编辑:
为了澄清这个场景,有以下几点:
<span class="blue">here is a lot of text that i don't need</span>
和
<span class="blue">this is the span i need because it contains 04/18/13 7:29pm</span>
并注意我只需要04/18/13 7:29pm其他内容.
编辑2:
我也尝试过:
pattern = re.compile('<span class="blue">.*?(\d\d/\d\d/\d\d \d\d?:\d\d\w\w)</span>')
for _ in new_content:
result = re.findall(pattern, _)
print result
并得到错误:
'TypeError: expected string or buffer'
Cor*_*erg 17
import re
from bs4 import BeautifulSoup
html_doc = """
<html>
<body>
<span class="blue">here is a lot of text that i don't need</span>
<span class="blue">this is the span i need because it contains 04/18/13 7:29pm</span>
<span class="blue">04/19/13 7:30pm</span>
<span class="blue">Posted on 04/20/13 10:31pm</span>
</body>
</html>
"""
# parse the html
soup = BeautifulSoup(html_doc)
# find a list of all span elements
spans = soup.find_all('span', {'class' : 'blue'})
# create a list of lines corresponding to element texts
lines = [span.get_text() for span in spans]
# collect the dates from the list of lines using regex matching groups
found_dates = []
for line in lines:
m = re.search(r'(\d{2}/\d{2}/\d{2} \d+:\d+[a|p]m)', line)
if m:
found_dates.append(m.group(1))
# print the dates we collected
for date in found_dates:
print(date)
输出:
04/18/13 7:29pm
04/19/13 7:30pm
04/20/13 10:31pm
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