PHP提交选择

Dan*_*Boy 6 html php submit

我试图没有提交按钮,当用户选择值时表单是否有任何提交方式?

<form method="post" action="<?php echo $_SERVER['PHP_SELF']  ?>" >

    <table class="form">

            <select name="category" class="formfield" id="category">
                <option value="-1"> Category </option>
                <?php
                    $sql_contry = "SELECT * FROM category";
                    $rs_c = mysql_query($sql_contry);
                    while ($row_c = mysql_fetch_array($rs_c)) {
                        echo '<option value="'.$row_c['category'].'">'.$row_c['category'].'</option>';  
                    }
                ?>
             </select>

    </table>

</form>
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The*_*ook 23

这是一个例子

<form>
    <select name='myfield' onchange='this.form.submit()'>
      <option selected>Milk</option>
      <option>Coffee</option>
      <option>Tea</option>
    </select>
    <noscript><input type="submit" value="Submit"></noscript>
</form>
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使用noscript标记,它允许不支持JavaScript的浏览器仍然可以运行.

  • +1用于非js用户的优雅降级 (9认同)

Adi*_*idi 4

是的 - 使用 JavaScript:

网页:

<form id="frm">
   <select onchange="onSelectChange();">
          <option>1</option>
           <option>1</option>
   <select>
</form>
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js:

function onSelectChange(){
 document.getElementById('frm').submit();
}
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